I have the following structure:
我有以下结构:
3 tables: movies, actors, genres
3桌:电影,演员,流派
Movies Table Schema:
电影表架构:
Schema::create('movies', function (Blueprint $t) {
$t->increments('id');
$t->string('title');
$t->integer('genre_id')->unsigned();
$t->foreign('genre_id')->references('id')->on('genres');
$t->string('genre');
$t->timestamps();
});
Genres Table Schema:
类型表架构:
Schema::create('genres', function (Blueprint $t) {
$t->increments('id');
$t->string('name');
$t->timestamps();
});
Actors Table Schema:
演员表架构:
Schema::create('actors', function (Blueprint $t) {
$t->increments('id');
$t->string('name');
$t->timestamps();
});
Movie Modal:
public function genre()
{
return $this->belongsTo('App\Genre');
}
public function actor()
{
return $this->belongsToMany('App\Actor');
}
Genre Modal:
public function movie()
{
return $this->hasMany('App\Movie');
}
Actor Modal:
public function movie()
{
return $this->belongsToMany('App\Movie');
}
Form:
<form method="post" action="{{ route('movies.insert') }}">
<input type="text" name="movieName" id="movieName">
<input type="text" name="actorName" id="actorName">
<input type="text" name="genre" id="genre">
<button type="submit">Add</button>
</form>
I am using the following controller method to post data from the form and everything is working fine but when I submit 2 movies with the same Genre, example "Action/Drama", I am getting 2 separate entries in the genres table like:
我使用以下控制器方法从表单发布数据,一切正常,但当我提交2个具有相同类型的电影,例如“动作/戏剧”时,我在流派表中得到2个单独的条目,如:
id: 1 name: Action/Drama
id:1 name:Action / Drama
id: 2 name: Action/Drama
id:2 name:Action / Drama
What is the best method to use a single id for a specific genre type over and over again? For example, if I add 10 movies with genre type 'Action/Drama', then the 'genre_id' foreign key in the 'movies' table should only show one specific id which corresponds with the genres table's 'Action/Drama' Id. Hope that makes sense :/
对于特定类型类型反复使用单个ID的最佳方法是什么?例如,如果我添加10个流派类型为“动作/戏剧”的电影,那么“电影”表中的“genre_id”外键应该只显示一个与流派表的“动作/戏剧”ID相对应的特定ID。希望有道理:/
Controller Method:
public function addMovies(Request $request)
{
$genre = new Genre;
$genre->name = $request->input('genre');
$genre->save();
$movie = new Movie;
$movie->title = $request->input('movieName');
$movie->genre = $request->input('genre');
$movie->genre()->associate($genre);
$movie->save();
$actor = new Actor;
$actor->name = $request->input('actorName');
$actor->save();
$actor->movie()->save($movie);
return redirect()->route('movies.search');
}
The output table should look something like this:
输出表应如下所示:
Note: I also have a pivot table which is connecting movies with actors to facilitate the many-to-many relation, but I haven't included it here.
注意:我还有一个数据透视表,它将电影与演员连接以促进多对多关系,但我没有在此处包含它。
1 个解决方案
#1
4
Well you are explicitly saving a new genre every time that's why you're getting duplicates. What you want to do is something like
那么你每次都明确地保存一个新的类型,这就是为什么你得到重复。你想做的就是这样
$genre = Genre::firstOrCreate("name", $request->input('genre'));
Then you'd assign the movie to the genre
然后你将电影分配到流派
#1
4
Well you are explicitly saving a new genre every time that's why you're getting duplicates. What you want to do is something like
那么你每次都明确地保存一个新的类型,这就是为什么你得到重复。你想做的就是这样
$genre = Genre::firstOrCreate("name", $request->input('genre'));
Then you'd assign the movie to the genre
然后你将电影分配到流派