Jay Chan 用
C 语言写的一个迷你版 2048 游戏,仅仅有 487 个字符。
来围观吧
M[16],X=16,W,k;main(){T(system("stty cbreak")
);puts(W&1? "WIN":"LOSE");}K[]={2,3,1};s(f,d,i
,j,l,P){for(i=4;i--;)for(j=k=l=0;k<4;)j<4? P=M
[w(d,i,j++)],W|=P>>11,l*P&&(f?M[w(d,i,k)]=l<<
(l==P):0,k++),l=l?P?l-P?P:0:l:P:(f?M[w(d,i,k)
]=l:0,++k,W|=2*!l,l=0);}w(d,i,j){return d?w(d
-1,j,3-i):4*i+j;}T(i){for(i=X+rand()%X;M[i%X]
*i;i--);i? M[i%X]=2<<rand()%2:0;for(W=i=0;i<4;
)s(0,i++);for(i=X,puts("\e[2J\e[H");i--;i%4||
puts(""))printf(M[i]?"%4d|":" |",M[i]);W-2
||read(0,&k,3)|T(s (1,K[(k>>X)%4]));}
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <time.h> #define GRID_LEN 16 int M[GRID_LEN];
int X = GRID_LEN;
int W;
int k;
int K[] = { 2, 3, 1 }; int w (int d, int i, int j)
{
if (d <= 0) {
return 4 * i + j;
} return w (d - 1, j, 3 - i);
} void s (int f, int d)
{
int i = 4, j, l, P; for (; i--;) {
j = k = l = 0; for (; k < 4;) {
if (j < 4) {
P = M[w (d, i, j++)];
W |= P >> 11;
l *P && (f ? M[w (d, i, k)] = l << (l == P) : 0, k++);
l = l ? (P ? (l - P ? P : 0) : l) : P;
}
else {
f ? M[w (d, i, k)] = l : 0;
++k;
W |= 2 * !l;
l = 0;
}
}
}
} void T ()
{
int i = X + rand () % X; for (; M[i % X] * i; i--); i ? M[i % X] = 2 << rand () % 2 : 0;
W = i = 0; for (; i < 4; i++) {
s (0, i);
} // Prints the tiles onto the terminal
i = X;
puts ("\e[2J\e[H"); for (; i--;) {
if (M[i]) {
printf ("%4d|", M[i]);
} else {
printf ("%s", " |");
} // every 4th cell is followed by a line-break
if (0 == (i & 3)) {
putchar ('\n');
}
} // read input from keyboard
if (!(W - 2)) {
read (0, &k, 3);
s (1, K[(k >> X) % 4]);
T ();
}
} int main (void)
{
// Uses stty to clear the screen in preparation for the game
//system ("stty cbreak"); /* Intializes random number generator */
srand ((unsigned) time (NULL)); T (); // Game has finished by this point
// If win, display "WIN". Otherwise, display "LOSE".
puts (W & 1 ? "WIN" : "LOSE"); return 0;
}