题目:统计一个数字在排序数组中出现的次数。例如,输入排序数组{1,2,3,3,3,3,4,5}和数字3由于3在这个数组中出现了4次,因此输出4。
#include <iostream>
using namespace std;
int getfirstk(int *a,int k,int low,int high)
{
if(low>high)
return -1;
int mid=(low+high)/2;
if(a[mid]==k)
{
if((mid>0&&a[mid-1]!=k)||mid==0)
return mid;
else
high=mid-1;
}
else if(a[mid]>k)
high=mid-1;
else
low=mid+1;
return getfirstk(a,k,low,high);
}
int getlastk(int *a,int k,int low,int high)
{
if(low>high)
return -1;
int mid=(low+high)/2;
if(a[mid]==k)
{
if((mid!=high&&a[mid+1]>k)||mid==high)
return mid;
else
low=mid+1;
}
else if(a[mid]>k)
high=mid-1;
else
low=mid+1;
return getlastk(a,k,low,high);
}
int main()
{
int a[]={1,2,3,3,3,3,4,5};
int first,last,x,k;
cin>>k;
int low=0,high=sizeof(a)/sizeof(a[0])-1;//high=8-1;
first=getfirstk(a,k,low,high);
last=getlastk(a,k,low,high);
if(first!=-1&&last!=-1)
{
x=last-first+1;
cout<<x;
}
}