算法:Rev(X)函数为翻转数字 输入两个数 求他们的 result=Rev(Rev(num1)+Rev(num2))

package test;

import java.util.Scanner;

/**
 * 算法 Rev(X)函数为翻转数字 输入两个数 求他们的 result=Rev(Rev(num1)+Rev(num2)) 若翻转后存在0，去除
 */
public class Test2{

public static void main(String[] args){
        Scanner scanner = new Scanner(System.in);
        String str1 = scanner.nextLine();
        String str2 = scanner.nextLine();
int str3;
        String result;
        str3=Rev(str1)+Rev(str2);
        result=String.valueOf(str3);
        str3 = Rev(result);
        System.out.println(str3);


    }
static int Rev(String str){
char temp=0;
        String newStr="";
char chars[] = str.toCharArray();
for(int i=0;i<chars.length/2;i++){
            temp=chars[i];
            chars[i] = chars[chars.length-i-1];
            chars[chars.length-i-1] = temp;
        }
for(int i=0;i<chars.length;i++){
if(chars[i]=='0' && (i==0 || i==chars.length-1)){
continue;
            }else {
                newStr += chars[i];
            }
        }
return Integer.parseInt(newStr);
    }

}