上机练习2
1、 启动SQL Server 2008中的 SQL Server Management Studio。
2、 针对下面三张基本表进行操作:
学生信息表(Student):
列名 |
数据类型 |
长度 |
是否可空 |
备注 |
学号 |
char |
4 |
N |
PRIMARY KEY |
姓名 |
varchar |
8 |
N |
|
性别 |
char |
2 |
Y |
男/女 |
出生日期 |
date |
Y |
||
家庭地址 |
varchar |
50 |
Y |
|
身高 |
decimal(3,2) |
Y |
||
备注 |
text |
Y |
课程表(Course):
列名 |
数据类型 |
长度 |
是否可空 |
备注 |
课程编号 |
Char |
4 |
N |
主键 |
课程名称 |
varchar |
50 |
N |
|
学分 |
int |
Y |
成绩表(Score):
列名 |
数据类型 |
长度 |
是否可空 |
备注 |
学号 |
Char |
4 |
N |
主键 |
课程编号 |
char |
4 |
N |
主键 |
分数 |
Decimal(3,1) |
Y |
3、 将下列数据输入各个表中
学号 |
姓名 |
性别 |
出生日期 |
家庭地址 |
身高 |
备注 |
0001 |
刘一平 |
男 |
1990-10-1 |
温州市环城西路201号 |
1.78 |
|
0002 |
张得民 |
男 |
1990-12-2 |
杭州市下沙路22号 |
1.65 |
|
0003 |
马东 |
男 |
1990-7-4 |
宁波市中山北道20号 |
1.71 |
|
0004 |
肖海燕 |
女 |
1990-3-15 |
温州市越秀北路43号 |
1.65 |
|
0005 |
张民华 |
女 |
1991-5-13 |
宁波市艮山路7号 |
1.63 |
课程编号 |
课程名称 |
学分 |
0001 |
计算机基础 |
2 |
0002 |
管理学原理 |
3 |
0003 |
数据库技术 |
3 |
0004 |
项目管理 |
2 |
0005 |
毕业论文 |
10 |
学号 |
课程编号 |
分数 |
0001 |
0001 |
80.0 |
0001 |
0002 |
90.0 |
0001 |
0003 |
70.0 |
0001 |
0004 |
85.0 |
0002 |
0001 |
78.0 |
0002 |
0002 |
NULL |
0002 |
0003 |
77.0 |
0002 |
0004 |
67.0 |
0003 |
0001 |
66.0 |
0003 |
0002 |
76.0 |
0003 |
0003 |
NULL |
0003 |
0004 |
73.0 |
、 为Student表添加“系名”字段,存储数据如:“信息系”,“数学系”,“计算机系”等,具体数据可自行添加到Student表中;
ALTER TABLE Student
ADD Sdept char(); 、 统计各个课程号及相应的选课人数;
SELECT Cno,COUNT(Sno)
FROM Score
GROUP BY Cno; 、 统计没有参加考试的学生学号和姓名;
SELECT Sno,Sname
FROM Student
WHERE Sno IN
(SELECT Sno
FROM Score
WHERE Sscore IS NULL); 、 查询选修了3门课以上的学生姓名;
SELECT Sname
FROM Student
WHERE Sno IN
(SELECT Sno
FROM Score
GROUP BY Sno
HAVING COUNT(*)>); 、 统计选修人数在3人以上的课程号和课程名;
SELECT Cno,Cname
FROM Course
WHERE Cno IN
(SELECT Cno
FROM Score
GROUP BY Cno
HAVING COUNT(*)>); 、 查询每个学生的学号、姓名、选修的课程名及成绩;
SELECT Student.Sno,Sname,Cname,Cscore
FROM Student,Score,Course
WHERE Student.Sno=Score.Sno AND Score.Cno=Course.Cno; 、 查询选修了课程号为“”的学生姓名和住址;
SELECT Sname,Saddr
FROM Student,Score
WHERE Score.Sno=Student.Sno AND Score.Cno=''; 、 查询与“刘一平”来自同一个系的学生姓名;
SELECT S2.Sname
FROM Student S1,Student S2
WHERE S1.Sdept=S2.Sdept AND S1.Sname='刘一平'; 、 查询其它系中课程‘’比信息系所有学生分数高的学生学号和姓名;
SELECT Sno,Sname
FROM Student
WHERE Sno IN
(SELECT Sno
FROM Score
WHERE Score.Cno='' AND Cscore>
(SELECT MAX(Cscore)
FROM Student,Score
WHERE Student.Sno=Score.Sno AND Cno='' AND Sdept='信息系'
)
AND Sdept<>'信息系'); 、 查询其它系中比信息系所有学生年龄大的学生姓名和性别;
SELECT Sname, Sgender
FROM Student
WHERE -YEAR(Sbirth)>ALL
(SELECT -YEAR(Sbirth)
FROM Student
WHERE Sdept='信息系'
) AND Sdept<>'信息系' ; 、 查询每门课程中低于该课程平均成绩的学生学号和姓名;
SELECT DISTINCT Score.Sno,Sname
FROM Student,Score
WHERE Student.Sno = Score.Sno
AND Score.Cscore<
(SELECT avgscore
FROM
(SELECT Cno,AVG(Cscore)
FROM Score
GROUP BY Cno)
AS AVGSC(Cno,avgscore)
WHERE Cno = Score.Cno); SELECT Student.Sno,Sname,Cno
FROM Student,Score A
WHERE Student.Sno = A.Sno
AND Cscore<
(SELECT AVG(Cscore)
FROM Score B
WHERE A.Cno = B.Cno); 我的:
SELECT Sno,Sname
FROM Student
WHERE Sno IN
(SELECT Sno
FROM Score A
WHERE Cscore<
(SELECT AVG(Cscore)
FROM Score B
WHERE A.Cno = B.Cno)); 、 查询“信息系”中选课最多的学生学号;
SELECT Score.Sno
FROM Score ,Student
WHERE Sdept ='信息系'
AND Score.Sno=Student.Sno
GROUP BY Score.Sno
HAVING COUNT(*)>=ALL
(SELECT COUNT(*)
FROM Score,Student
WHERE Sdept='信息系'
AND Score.Sno=Student.Sno
GROUP BY Score.Sno); SELECT TOP Score.Sno, COUNT(*) NumOfCourse
FROM Student,Score
WHERE Sdept='信息系' AND student.Sno=Score.Sno
GROUP BY Score.Sno
ORDER BY NumOfCourse DESC ; SELECT TOP Student.Sno
FROM
(SELECT Sno,COUNT(*)
FROM Score
GROUP BY sno)
AS st(sno,cnt),Student
WHERE st.sno=Student.Sno AND Student.Sdept='信息系'
ORDER BY st.cnt DESC ; 、 查询有两门及以上课程不及格的学生学号和姓名;
SELECT Sname,Sno
FROM Student
WHERE Sno IN
(SELECT s1.Sno
FROM
(SELECT *
FROM Score
WHERE Cscore<) s1
GROUP BY s1.Sno
HAVING COUNT(*)>); 我的:
SELECT Sno,Sname
FROM Student
WHERE
(SELECT COUNT(*) FROM Score WHERE Student.Sno=Score.Sno AND
(Cscore< OR Cscore=NULL))>=; 、 查询比“”号课程平均分高的其它课程信息;
我的:
SELECT Course.*
FROM Course,Score A
WHERE Course.Cno = A.Cno AND
A.Cno!='' AND
(SELECT AVG(Cscore)
FROM Score B
WHERE A.Cno=B.Cno)>
(SELECT AVG(Cscore)
FROM Score
WHERE Cno ='') SELECT *
FROM Course
WHERE Cno IN
(SELECT Cno
FROM Score
GROUP BY Cno
HAVING Cno <> '' AND AVG(Cscore)>
(SELECT AVG(Cscore)
FROM Score
GROUP BY Cno
HAVING Cno = '')); 、 查询选修了所有课程的学生学号和姓名。
我的:
SELECT Sno,Sname
FROM Student
WHERE NOT EXISTS
(SELECT *
FROM Course
WHERE NOT EXISTS
(SELECT *
FROM Score
WHERE Sno = Student.Sno
AND Cno=Course.Cno)); SELECT Sno
FROM Score
GROUP BY Sno
HAVING COUNT(*) =
(SELECT COUNT(*)
FROM Course);