如何使用“多对多”关系的标准?

时间:2021-08-17 07:05:25

Good afternoon. Learn Hibernate, it became necessary to write the following query using the criteria. There are two entities - a fruit shop and the type of communication - many to many. Accordingly, we have literally three tables (and the corresponding classes of Java): Fruit (id, name), Shop (id, name) and ShopFruit (shop_id, fruit_id). So, as with the criterion to obtain a list of stores selling, say, a tangerine? Thanks in advance.

下午好。学习Hibernate,有必要使用条件编写以下查询。有两个实体 - 一个水果店和通信类型 - 许多人。因此,我们实际上有三个表(以及相应的Java类):Fruit(id,name),Shop(id,name)和ShopFruit(shop_id,fruit_id)。那么,正如获得销售商店列表的标准一样,比如橘子?提前致谢。

1 个解决方案

#1


0  

I think you can use an alias like so:

我想你可以使用这样的别名:

List questions = session.createCriteria(Shop.class)
  .createAlias("Fruits", "f")
  .add(Restrictions.eq("f.name", "tangerine"))
  .list();

See also this question. However, I think you can also solve this with a set in your Hibernate mapping for Fruit:

另见这个问题。但是,我认为你也可以用你的Hibernate映射中的一个集合解决这个问题:

<set name="stores" table="ShopFruit" cascade="all">
  <key column="fruit_id" />
  <many-to-many column="store_id" />
</set>

Extends your Fruit class with a stores set:

使用商店集扩展您的Fruit类:

class Fruit {
  ...
  Set<Store> stores;
  ...
}

If you than load the "tangerine" Fruit object from the database, the stores variable should have all the stores selling it.

如果您要从数据库加载“tangerine”Fruit对象,那么stores变量应该包含销售它的所有商店。

#1


0  

I think you can use an alias like so:

我想你可以使用这样的别名:

List questions = session.createCriteria(Shop.class)
  .createAlias("Fruits", "f")
  .add(Restrictions.eq("f.name", "tangerine"))
  .list();

See also this question. However, I think you can also solve this with a set in your Hibernate mapping for Fruit:

另见这个问题。但是,我认为你也可以用你的Hibernate映射中的一个集合解决这个问题:

<set name="stores" table="ShopFruit" cascade="all">
  <key column="fruit_id" />
  <many-to-many column="store_id" />
</set>

Extends your Fruit class with a stores set:

使用商店集扩展您的Fruit类:

class Fruit {
  ...
  Set<Store> stores;
  ...
}

If you than load the "tangerine" Fruit object from the database, the stores variable should have all the stores selling it.

如果您要从数据库加载“tangerine”Fruit对象,那么stores变量应该包含销售它的所有商店。