Github leetcode 我的解题仓库 https://github.com/interviewcoder/leetcode
题目:
Implement strStr().
Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.
Update (2014-11-02):
The signature of the function had been updated to return the index instead of the pointer. If you still see your function signature returns a char *
or String
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Tag:
String; Two Pointers
体会:
这道题是字符串的匹配问题,目前还只会朴素的逐步方法,但是这道题还有KMP解法,和Boyer-Moore的解法,目前还没有掌握。
先把笔记放到这里,以后再来解决吧。
1. KMP算法
class Solution {
public:
int strStr(char *haystack, char *needle) {
int i = ; // index under examine in haystack
int j = ; // index under examine in needle while (haystack[i] && needle[j]) {
if (haystack[i] == needle[j]) {
i++;
j++;
} else {
// roll back:
// reset haystack index back to (i - j + 1), since in current examine
// start index in haystack is (i - j)
i = i - j + ;
// reset needle back to its beginning
j = ;
}
}
// if haystack ends but needle not ends,
// we know needle is not in the haystack, then return -1.
return (needle[j]) ? - : (i - j);
}
};