1、设计一个类（不妨叫做A ），实现对一维数组(a[100])的指定范围内的元素相加运算。
程序代码如下：
package df;
import java.util.Scanner;//用于java输入语句的包。
public class a {
public static void main(String[]args)
{
int[] w={-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767};//直接将数据copy过来
int sum=0;
Scanner hh = new Scanner(System.in) ;//实例化。
System.out.println("从第几个数开始:");
int start = hh.nextInt() ; //这里用到Scanner类的nextInt()方法
System.out.println("到第几个数结束:");
int end =hh.nextInt();
System.out.println("开始为：" +start);
System.out.println("结束为：" +end);
for(int i=start;i<=end;i++)
sum+=w[i];
System.out.println(sum);
}
}
代码运行如下：
2、 设计一个类（不妨叫做B ），实现对二维数组的指定范围内的元素相加运算。
程序代码如下：
package df;
import java.util.Scanner;
public class b {
public static void main(String[]args){
int[][]b={
{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767},
{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}
};
int sum=0;
Scanner hh = new Scanner(System.in);
System.out.println("从第几行开始:");//一共两行
int begin1 = hh.nextInt();
System.out.println("到第几行结束:");
int over1 =hh.nextInt();
System.out.println("从第几列开始:");//<=100
int begin2 = hh.nextInt();
System.out.println("到第几列结束:");
int over2 =hh.nextInt();
System.out.println("第"+begin1+"行第"+begin2+"列到第"+over1+"行第"+over2+"列的和为：");
for(int i=begin1-1;i<=over1-1;i++)
{
for(int j=begin2-1;j<=over2-1;j++)
{
sum+=b[i][j];
}
}
System.out.println(sum);
}
}
代码运行结果：
3、 设计一个类（不妨叫做C ），实现对三维数组的指定范围内的元素相加运算
代码如下：
package df;
import java.util.Scanner;
public class c {
public static void main(String[]args)
{
int sum=0;
int[][][] a = new int[][][]
{
{{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767}},
{{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}},
{{302,-7944,-6551,6648,-884,-6332,1188,-248,3902,-2171,-3782,-3510,6203,-636,-4605,4497,3187,-6278,1198,-7963,7647,-3022,-8267,7995,-1998,-4171,730,-8117,-1706,7601,-2454,-6161,-1810,243,-2841,-5377,2985,2328,177,5622,3596,3057,2830,-1151,6566,2254,6972,-3060,4063,367,84,3156,3880,-1530,5272,1385,-565,-1736,1267,-3863,-229,2072,2423,-7449,9555,2844,-1278,-3613,-919,4153,-4232,4032,-5732,199,4792,2498,-3344,-4193,2650,-579,3416,-3575,1822,-6936,-2661,-1873,414,2314,6844,7613,-7844,6680,5974,2208,-3597,6302,4396,-141,-1864,1939}}
};
Scanner hh = new Scanner(System.in) ;
System.out.println("开始x:");
int start1 = hh.nextInt() ;
System.out.println("结束x:");
int end1 =hh.nextInt();
System.out.println("开始x为：" +start1);
System.out.println("结束x为：" +end1);
System.out.println("开始y:");
int start2 = hh.nextInt() ;
System.out.println("结束y:");
int end2 =hh.nextInt();
System.out.println("开始y：" +start2);
System.out.println("结束y为：" +end2);
System.out.println("开始z:");
int start3 = hh.nextInt() ;
System.out.println("结束z:");
int end3 =hh.nextInt();
System.out.println("开始z为：" +start3);
System.out.println("结束z为：" +end3);
for(int i=start1;i<=end1;i++)
{
for(int j=start2;j<=end2;j++)
{
for(int q=start3;q<=end3;q++)
{
sum+=a[i][j][q];
}
}
}
System.out.println("相加结果为:") System.out.println(sum);
}
}
代码运行如下：
4、总结
在老师布置这次作业的时候，便联想到大二时曾经学过Java中用for语句1+2+3+.....+100的问题，但是结合题目看了看好像自己想的太简单了，于是便又去查询了一下课本，发现似乎可以运用Scanner类的nextInt（）方法再加上for循环语句加以解决这个问题。但是对于以前知识薄弱的我来说写这个程序还是有点儿困难，于是便去请教室友，在室友的帮助下，终于渐渐有了代码雏形，便开始自己动手去写，可是在调试的过程中，一直出现错误，但是找了半天却依旧找不出来，幸亏老师有推荐两位写的比较好的同学的作业，于是便却拜读了一下，才发现自己对于数组取值的范围太过随便。最后终于得出了结果。这次作业，让我深刻明白自己在这方年面的欠缺，当然也体验到合作完成任务的快乐。希望以后能够渐渐完善自己，在以后的作业完成的过程中更进一步。