python初级练习题

草稿(代码未补充完毕)

a. 元素分类

#追加练习
有如下值集合 v1 = [11,22,33,44,55,66,77,88,99,90]，
将所有大于 66 的值保存至字典的第一个key中，将小于 66 的值保存至第二个key的值中。
即： {'k1': 大于66的所有值, 'k2': 小于66的所有值}

v2 = {'k1': [],'k2':[] }

#!/usr/bin/python
# -*- coding utf8 -*-

V1 = [11,22,33,44,55,66,77,88,99,90]
V2=[]
V3=[]
print(V1)
for item in V1:
    print(item)
    if item > 66:
        V2.append(item)
    else:
        V2.append(item)
VD = {'K1': V1, 'K2': V2}
print(VD)

#注意变量格式
b. 功能要求：
v = 2000
要求用户输入总资产，例如：2000
显示商品列表，让用户根据序号选择商品，加入购物车
购买，如果商品总额大于总资产，提示账户余额不足，否则，购买成功。
goods = [
{"name": "电脑", "price": 1999},
{"name": "鼠标", "price": 10},
{"name": "游艇", "price": 20},
{"name": "美女", "price": 998},
]

num = input('>>>') # 1
num = int(num)

goods[num]['price']

goods = [
    {"name": "电脑", "price": 1999},
    {"name": "鼠标", "price": 10},
    {"name": "游艇", "price": 20},
    {"name": "美女", "price": 998},
]
sum_num = input('请输入你的总资产')
i = 1
for item in goods:
    print(i)
    i += 1
    for k, v in item.items():
        if k == 'name':
            print("商品名称:", item[k])
        elif k == 'price':
            print("商品价格:", item[k])
    print('--------')


goods_name = input('请输入要购买的商品编号: ')
len_val = len(goods_name)
i = 0
sum_goods = 0
while i < len_val:
    val = int(goods_name[i])
    price = int(goods[int(val) - 1]['price'])
    sum_goods += price
    i += 1
result = int(sum_num) - int(sum_goods)
if result >= 0:
    print('购买成功')
else:
    print("钱不够了")

此示例的高级扩展参考: http://blog.csdn.net/wuxingpu5/article/details/71602770

#显示让用户选择
c. 用户交互，显示省市县三级联动的选择

dic = {
"河北": {
"石家庄": ["鹿泉", "藁城", "元氏"],
"邯郸": ["永年", "涉县", "磁县"],
}
"河南": {
...
}
"山西": {
...
}
}

for v in dic.keys():
print(v)
inp = input('>>>')

dic[inp]

china_dic = {
    "河北": {
        "石家庄": ["鹿泉", "藁城","元氏", "高邑"],
        "邯郸": ["永年", "涉县", "磁县"],
    },
    "河南": {
        "郑州": ["新密", "新郑", "登封"],
        "开封": ["通许", "兰考", ],
    }
}

pro = input("请输入省份")
for item in china_dic.keys():
    if item == pro:
        print(china_dic[pro])
        city_name = input('请输入城市名字: ')
        for city in china_dic[pro].keys():
            if city == city_name:
                print(china_dic[item][city])
                break

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python初级练习题

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