【简单】Lintcode 9:Fizz Buzz

Given number n. Print number from 1 to n. But:

• when number is divided by 3, print "fizz".
• when number is divided by 5, print "buzz".
• when number is divided by both 3 and 5, print "fizz buzz".

Example

If n = 15, you should return:

[
  "1", "2", "fizz",
  "4", "buzz", "fizz",
  "7", "8", "fizz",
  "buzz", "11", "fizz",
  "13", "14", "fizz buzz"
]

解题思路：

1、非常简单，不过要对vector类的成员函数有所了解，最后一种情况需要将int型数据push_back进入，可是push_back()函数只接受它本身的string类型，不能直接传递，这里需要把int转换为string，用to_string()函数即可。

class Solution {
public:
    /*
     * @param n: An integer
     * @return: A list of strings.
     */
    vector<string> fizzBuzz(int n) 
    {
        // write your code here
        vector<string> temp;
        
        for(int i=1;i<=n;i++)
        {
            if(i%3==0 && i%5==0)
            {
                temp.push_back("fizz buzz");
            }
            else if(i%3==0)
            {
                temp.push_back("fizz");
            }
            else if(i%5==0)
            {
                temp.push_back("buzz");
            }
            else
            {
                temp.push_back(to_string(i));
            }
        }
        
        return temp;
    }
};