从完整文件路径中查找文件名

Is there a way to extract the file name from the file full path (part of a file path) without the hassle of manipulating string?

是否有一种方法可以从文件完整路径(文件路径的一部分)中提取文件名而不需要处理字符串?

The equivalent in Java would be:

在Java中相当于:

File f = new File ("C:/some_dir/a")
f.getName() //output a
f.getFullAbsolutePath() //output c:/some_dir/a

1 个解决方案

#1

Use

使用

basename("C:/some_dir/a.ext")
# [1] "a.ext"
dirname("C:/some_dir/a.ext")
# [1] "C:/some_dir"