解决不用sizeof求出int大小的方法

代码如下所示：

复制代码 代码如下:

#include <stdio.h> 
int main(int argc, char *argv[]) 
{ 
    int a[2]; 
    unsigned int add1 = &a[0]; 
    unsigned int add2 = &a[1]; 
    printf("The address of a[0] is %u/n",add1); 
    printf("The address of a[1] is %u/n",add2); 
    printf("The size of int is %u/n", add2 - add1); 
}

输出结果是：
The address of a[0] is 3218821936
The address of a[1] is 3218821940
The size of int is 4