I have a button to copy data from a user uploaded file to the clipboard in a specific format. I already have that data saved in the database as it was uploaded in a separate file form. I currently have it so that upon clicking the copy to clipboard button it is linked to a copy_data view in my views.py that requires an HTTP request which redirects to the current template containing the copy to clipboard button with something like this:
我有一个按钮，用于将用户上传文件中的数据以特定格式复制到剪贴板。我已经将数据保存在数据库中，因为它是以单独的文件形式上传的。我目前拥有它，以便在单击复制到剪贴板按钮时，它链接到我的views.py中的copy_data视图，该视图需要HTTP请求，该请求重定向到包含复制到剪贴板按钮的当前模板，如下所示：
HttpResponseRedirect('previous/template/here')
HttpResponseRedirect（ '一/模板/这里'）
This works fine except for the fact that since it links to my copy_data view which then redirects to the original view containing the button it reloads the entire page which is undesirable.
这很好用，因为它链接到我的copy_data视图，然后重定向到包含按钮的原始视图，它重新加载整个页面，这是不可取的。
I think a better solution would be to somehow bind a python function directly to the button click rather than worrying about redirecting from one view to another.
我认为更好的解决方案是以某种方式将python函数直接绑定到按钮单击，而不是担心从一个视图重定向到另一个视图。
I've found many examples using ajax, but haven't found any that work for my use case. I tried binding a click event to the button without any problems, but I am stuck on figuring out how to bind the python function with the click.
我发现很多使用ajax的例子，但是没有找到任何适用于我的用例。我尝试将单击事件绑定到按钮没有任何问题，但我仍然坚持要弄清楚如何将python函数与click结合。
How can I bind a python function in my Django template upon a button press?
如何在按下按钮的情况下在我的Django模板中绑定python函数？
1 个解决方案
#1
1
It's tough to tell for sure, but I think you're mixing synch/asynch paradigms here. When you generate requests with Ajax, you don't (generally) want to return a redirect, you want to return data. That might be JSON data or data formatted as a specific MIME type or even just text. One way this might look at a high level is:
很难说清楚，但我认为你在这里混合使用synch / asynch范例。当您使用Ajax生成请求时，您（通常）不希望返回重定向，而是希望返回数据。这可能是JSON数据或格式化为特定MIME类型的数据，甚至只是文本。这可能是高层次的一种方式：
def copy_data(request):
# get posted data
submitted = request.POST
# do whatever is necessary to create document
data = ???
# first, we'll need a response
resp = HttpResponse()
# set the content type, if needed
resp.content_type = 'text/???; charset=utf-8'
# response has a file-like interface
resp.write(data)
return resp
Obviously, this would need work to suit your purpose, but that's the high-level approach.
显然，这需要适合您的目的，但这是高级方法。
It doesn't sound like you're returning JSON, but there's a special response object for that now if you need it.
这听起来并不像你正在返回JSON，但如果你需要它，现在有一个特殊的响应对象。
#1
1
It's tough to tell for sure, but I think you're mixing synch/asynch paradigms here. When you generate requests with Ajax, you don't (generally) want to return a redirect, you want to return data. That might be JSON data or data formatted as a specific MIME type or even just text. One way this might look at a high level is:
很难说清楚，但我认为你在这里混合使用synch / asynch范例。当您使用Ajax生成请求时，您（通常）不希望返回重定向，而是希望返回数据。这可能是JSON数据或格式化为特定MIME类型的数据，甚至只是文本。这可能是高层次的一种方式：
def copy_data(request):
# get posted data
submitted = request.POST
# do whatever is necessary to create document
data = ???
# first, we'll need a response
resp = HttpResponse()
# set the content type, if needed
resp.content_type = 'text/???; charset=utf-8'
# response has a file-like interface
resp.write(data)
return resp
Obviously, this would need work to suit your purpose, but that's the high-level approach.
显然，这需要适合您的目的，但这是高级方法。
It doesn't sound like you're returning JSON, but there's a special response object for that now if you need it.
这听起来并不像你正在返回JSON，但如果你需要它，现在有一个特殊的响应对象。