题意:
The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)
should return "PAHNAPLSIIGYIR"
. (Easy)
分析:
首先是理解题意,题目例子举得不好...起始ZigZag的意思以4举例更易懂一些。
1 7 13
2 6 8 12
3 5 9 11
4 10
读懂了题意,其实就是判断好什么时候向下,什么时候向上即可,我用的vector<string>实现,维护nRows个string,最后拼接在一起。
代码:
class Solution {
public:
string convert(string s, int numRows) {
if (numRows == ) {
return s;
}
vector<string> v(numRows);
int j = ;
for (int i = ; i < s.size(); ++i) {
if ( (i / (numRows - ) ) % == ) {
v[j].insert(v[j].end(), s[i]);
j ++;
}
if ( (i / (numRows - )) % == ) {
v[j].insert(v[j].end(), s[i]);
j--;
}
}
string result;
for (int i = ; i < v.size(); ++i) {
result += v[i];
}
return result;
}
};