如何使rp和xrange动态?

Hey guys many thanks for taking the time to look at my problem, I have been working on this code for about 1 week (I am new to coding and to python 1 week also) Currently the loop only works if x in xrange(x) and 'rp' : 'x' is the correct number of rows available from this xml. The xml updates throughout the day, I was wondering if anyone can offer a solution to make x dynamic?

嘿家伙很多谢谢你花时间看我的问题,我一直在这工作代码大约1周(我新编码和python 1周)目前在xrange循环只能如果x(x)和“rp”:“x”是正确的可以从这个xml的行数。一整天的xml更新，我想知道是否有人能提供一个使x动态的解决方案?

import mechanize
import urllib
import json
import re
from sched import scheduler
from time import time, sleep

from sched import scheduler
from time import time, sleep

s = scheduler(time, sleep)

def run_periodically(start, end, interval, func):
event_time = start
while event_time < end:
    s.enterabs(event_time, 0, func, ())
    event_time += interval
s.run()

def getData():  
post_url = "urlofinterest_xml"
browser = mechanize.Browser()
browser.set_handle_robots(False)
browser.addheaders = [('User-agent', 'Firefox')]

######These are the parameters you've got from checking with the aforementioned tools
parameters = {'page' : '1',
              'rp' : '8',
              'sortname' : 'roi',
              'sortorder' : 'desc'
             }
#####Encode the parameters
data = urllib.urlencode(parameters)
trans_array = browser.open(post_url,data).read().decode('UTF-8')

xmlload1 = json.loads(trans_array)
pattern1 = re.compile('>&nbsp;&nbsp;(.*)<')
pattern2 = re.compile('/control/profile/view/(.*)\' title=')
pattern3 = re.compile('<span style=\'font-size:12px;\'>(.*)<\/span>')
pattern4 = re.compile('title=\'Naps posted: (.*) Winners:')
pattern5 = re.compile('Winners: (.*)\'><img src=')


for i in xrange(8):
    user_delimiter = xmlload1['rows'][i]['cell']['username']
    selection_delimiter = xmlload1['rows'][i]['cell']['race_horse']

    username_delimiter_results = re.findall(pattern1, user_delimiter)[0]
    userid_delimiter_results = int(re.findall(pattern2, user_delimiter)[0])
    user_selection = re.findall(pattern3, selection_delimiter)[0]
    user_numberofselections = float(re.findall(pattern4, user_delimiter)[0])
    user_numberofwinners = float(re.findall(pattern5, user_delimiter)[0])

    strikeratecalc1 = user_numberofwinners/user_numberofselections
    strikeratecalc2 = strikeratecalc1*100

    print "user id = ",userid_delimiter_results
    print "username = ",username_delimiter_results
    print "user selection = ",user_selection
    print "best price available as decimal = ",xmlload1['rows'][i]['cell']     ['tws.best_price']
    print "race time = ",xmlload1['rows'][i]['cell']['race_time']
    print "race meeting = ",xmlload1['rows'][i]['cell']['race_meeting']
    print "ROI = ",xmlload1['rows'][i]['cell']['roi']
    print "number of selections = ",user_numberofselections
    print "number of winners = ",user_numberofwinners
    print "Strike rate = ",strikeratecalc2,"%"
    print ""


getData()


run_periodically(time()+5, time()+1000000, 15, getData)

Kind regards AEA

亲切的问候AEA

2 个解决方案

#1

First, I'm going to talk about how you iterate over your results. Based on your code, xmlload1['rows'] is an array of dicts, so instead of choosing an arbitrary number, you can iterate over it directly instead. To make this a better example, I'm going to set up some arbitrary data to make this clear:

首先，我将讨论如何迭代结果。根据您的代码，xmlload1['rows']是一个dicts数组，因此您可以直接迭代它，而不是选择任意的数字。为了让这成为一个更好的例子，我将设置一些任意的数据来说明这一点:

xmlload1 = {
   "rows": [{"cell": {"username": "one", "race_horse":"b"}}, {"cell": {"username": "two", "race_horse": "c"}}]
}

So, given the data above, you can just iterate through rows in a for loop, like this:

因此，根据上面的数据，您可以在for循环中遍历行，如下所示:

for row in xmlload1['rows']:
    cell = row["cell"]
    print cell["username"]
    print cell["race_horse"]

Each iteration, cell takes on the value of another element in the iterable (the list in xmlload1['rows']). This works with any container or sequence that supports iteration (like lists, tuples, dicts, generators, etc.)

每一次迭代，单元格都在iterable (xmlload1['rows']中的列表)中接受另一个元素的值。这适用于任何支持迭代的容器或序列(如列表、元组、句、生成器等)。

Notice how I haven't used any magic numbers anywhere, so xmlload1['rows'] could be arbitrarily long and it would still work.

注意，我没有在任何地方使用任何神奇的数字，所以xmlload1['rows']可以是任意长，而且它仍然可以工作。

You can set the requests to be dynamic by using a function, like this:

您可以使用如下函数将请求设置为动态的:

def get_data(rp=8, page=1):
    parameters = {'page' : str(page),
              'rp' : str(rp),
              'sortname' : 'roi',
              'sortorder' : 'desc'
             }
    data = urllib.urlencode(parameters)
    trans_array = browser.open(post_url,data).read().decode('UTF-8')
    return json.loads(trans_array)

Now, you can call get_data(rp=5) to get 5 rows, or get_data(rp=8) to get 8 rows [and get_data(rp=8, page=3) to get the third page], etc. And you can clearly add additional variables or even pass in the parameters dict to the function directly.

现在，您可以调用get_data(rp=5)来获得5行，或者get_data(rp=8)来获得8行[以及get_data(rp=8, page=3)来获得第三页]，您可以清楚地添加额外的变量，甚至直接将参数dict类型传递给函数。

#2

I'm not sure I understand your question, but I think what you want is this:

我不确定我是否理解你的问题，但我认为你想要的是:

rows = xmlload1['rows']
for row in rows:
    user_delimiter = row['cell']['username']
    selection_delimiter = row['cell']['race_horse']
    # ...

If you need the row index as well as the row itself, use enumerate:

如果需要行索引和行本身，请使用enumerate:

rows = xmlload1['rows']
for i, row in enumerate(rows):
    user_delimiter = row['cell']['username']
    selection_delimiter = row['cell']['race_horse']
    # ...

In general, if you're doing for i in range(…) for any purpose other than a fixed number of iterations, you're doing it wrong. There's usually a collection you want to iterate over; just find it and iterate over it.

总的来说，如果你为我在range(…)中做任何事情，除了固定次数的迭代，你做错了。通常有一个集合需要迭代;只要找到它并迭代它。

#1

xmlload1 = {
   "rows": [{"cell": {"username": "one", "race_horse":"b"}}, {"cell": {"username": "two", "race_horse": "c"}}]
}