data <- structure(list(W= c(1L, 3L, 6L, 4L, 9L), X = c(2L, 5L,
4L, 5L, 12L), Y = c(4L, 4L, 6L, 6L, 16L), Z = c(3L, 5L,
6L, 7L, 6L)), .Names = c("W", "X", "Y", "Z"),
class = "data.frame", row.names = c(NA, -5L))
colours <- c("red", "orange", "blue", "yellow", "green")
barplot(as.matrix(data), main="My Barchart", ylab = "Numbers",
cex.lab = 1.5, cex.main = 1.4, beside=TRUE, col=colours).
That works fine but I need to order each group (separately) by decreasing, i.e. show the same plot but order from high to low for W
, …, Z
. Example: for W, green will be first from left, blue, yellow, … . For x
, green will be first from left, orange, yellow and so on.
这个方法很好,但是我需要通过减少来对每一组(分别)进行排序,也就是说,对于W,…,z,从高到低,显示相同的图形。对于x,绿色是从左开始,橙色,黄色等等。
1 个解决方案
#1
3
This can be achieved by generating the colors vector which has as many elements as there are bars and sorting each matrix column separately:
这可以通过生成颜色向量来实现,颜色向量的元素与条形的元素一样多,并分别对每个矩阵列进行排序:
sort the colors according to x order for each column and convert to vector:
根据每一列的x顺序对颜色进行排序,并转换为矢量:
colours <- as.vector(apply(data, 2, function(x){
col <- colours[order(x)]
}))
sort each column separetely:
区分每一列:
df <- apply(data, 2, sort)
barplot(df,
main = "My Barchart",
ylab = "Numbers",
cex.lab = 1.5,
cex.main = 1.4,
beside = TRUE,
col = colours)
for descending order and with legend
用于降序和图例
colours <- c("red", "orange", "blue", "yellow", "green")
colours1 <- as.vector(apply(data, 2, function(x){
col <- colours[order(x, decreasing = TRUE)]
}))
barplot(apply(data, 2, sort, decreasing = TRUE),
main = "My Barchart",
ylab = "Numbers",
cex.lab = 1.5,
cex.main = 1.4,
beside = TRUE,
col = colours1)
legend("topleft", c("First","Second","Third","Fourth","Fifth"), cex=1.3, bty="n", fill=colours)
Here one color vector was used to color the bars and another for the legend
在这里,一个颜色向量被用来给条形图上色,另一个用于图例
and finally for the question in the comments about aggregated data:
最后,关于聚合数据评论中的问题:
all <- apply(data, 1, mean)
colours <- c("red", "orange", "blue", "yellow", "green")
barplot(sort(all, decreasing = T), col = colours[order(all, decreasing = T)])
#1
3
This can be achieved by generating the colors vector which has as many elements as there are bars and sorting each matrix column separately:
这可以通过生成颜色向量来实现,颜色向量的元素与条形的元素一样多,并分别对每个矩阵列进行排序:
sort the colors according to x order for each column and convert to vector:
根据每一列的x顺序对颜色进行排序,并转换为矢量:
colours <- as.vector(apply(data, 2, function(x){
col <- colours[order(x)]
}))
sort each column separetely:
区分每一列:
df <- apply(data, 2, sort)
barplot(df,
main = "My Barchart",
ylab = "Numbers",
cex.lab = 1.5,
cex.main = 1.4,
beside = TRUE,
col = colours)
for descending order and with legend
用于降序和图例
colours <- c("red", "orange", "blue", "yellow", "green")
colours1 <- as.vector(apply(data, 2, function(x){
col <- colours[order(x, decreasing = TRUE)]
}))
barplot(apply(data, 2, sort, decreasing = TRUE),
main = "My Barchart",
ylab = "Numbers",
cex.lab = 1.5,
cex.main = 1.4,
beside = TRUE,
col = colours1)
legend("topleft", c("First","Second","Third","Fourth","Fifth"), cex=1.3, bty="n", fill=colours)
Here one color vector was used to color the bars and another for the legend
在这里,一个颜色向量被用来给条形图上色,另一个用于图例
and finally for the question in the comments about aggregated data:
最后,关于聚合数据评论中的问题:
all <- apply(data, 1, mean)
colours <- c("red", "orange", "blue", "yellow", "green")
barplot(sort(all, decreasing = T), col = colours[order(all, decreasing = T)])