one common solution in Excel to SUMIF() with multiple conditions goes like this (this formula counts all cases in which column A has the value in C1 and column B has the value in D1):
Excel中的一个常见解决方案是SUMIF(),具有多个条件(这个公式计算所有情况,其中列A的值在C1中,列B的值在D1中):
=SUMPRODUCT((A1:A9=C1)*(B1:B9=D1))
I, now, need a function that concatenated strings from lines fulfilling multiple conditions. There is a great solution for one condition at http://www.ms-office-forum.net/forum/showthread.php?t=273352
我现在需要一个函数来连接满足多个条件的行的字符串。 http://www.ms-office-forum.net/forum/showthread.php?t=273352对于一个条件有一个很好的解决方案
I, however, want to check multiple conditions - and therefore use the SUBPRODUCT() trick from above. My problem is: How do I have to define the parameter in the function to get an Array? This is what I got so far:
但是,我想检查多个条件 - 因此使用上面的SUBPRODUCT()技巧。我的问题是:如何在函数中定义参数以获取数组?这是我到目前为止所得到的:
' **********************************************************************
' Modul: Modul1 Typ: Allgemeines Modul
' **********************************************************************
Option Explicit
Public Function CONCATIF(Kriterium, Inhalte)
Dim mydic As Object
Dim L As Long
Set mydic = CreateObject("Scripting.Dictionary")
For L = 1 To UBound(Kriterium)
If Kriterium(L, 1) = 1 Then
If Inhalte(L, 1) <> "" Then
mydic(L) = Inhalte(L, 1)
End If
End If
Next
CONCATIF = Join(mydic.items, vbCrLf)
End Function
This works fine, if I select one columns for parameter 1. But as soon as I include a product formula (like above), only a Variant/Double with the value 1 is passed for Kriterium.
如果我为参数1选择一列,这样可以正常工作。但是只要我包含一个产品公式(如上所述),就只会为Kriterium传递一个值为1的Variant / Double。
=CONCATIF(A1:A9; E1:E9) Works fine (if column A is 0/1 coded)
=CONCATIF((A1:A9=C1)*(B1:B9=D1); E1:E9) Does not work at all
Any suggestions? Thank you!
有什么建议么?谢谢!
2 个解决方案
#1
2
The problem was because formula:
问题是因为公式:
=CONCATIF((A1:A9=C1)*(B1:B9=D1); E1:E9)
need to be called by pressing CTRL+SHIFT+ENTER
需要通过按CTRL + SHIFT + ENTER来调用
#2
0
For the sake of completeness, here's the complete Excel VBA Macro to concatenate strings from a range (may have multiple string columns), if criteria in other columns are matched.
为了完整起见,这里是完整的Excel VBA宏,用于连接范围中的字符串(可能有多个字符串列),如果其他列中的条件匹配。
' **********************************************************************
' Modul: Modul1 Typ: Allgemeines Modul
' **********************************************************************
Option Explicit
Public Function CONCATIF(Kriterium, Inhalte)
Dim mydic As Object
Dim L As Long
Dim C As Long
Dim N As Long
Dim cols As Long
Set mydic = CreateObject("Scripting.Dictionary")
cols = Inhalte.Columns.Count
N = 1
For L = 1 To UBound(Kriterium)
If Kriterium(L, 1) = 1 Then
For C = 1 To cols
If Not IsEmpty(Inhalte(L, C)) Then
mydic(N) = "* " & Inhalte(L, C)
N = N + 1
End If
Next
End If
Next
CONCATIF= Join(mydic.items, vbCrLf)
End Function
Use as follows - and don't forget to enter by CTRL+SHIFT+ENTER
使用如下 - 并且不要忘记通过CTRL + SHIFT + ENTER输入
=CONCATIF((A1:A:9="male")*(B1:B9="young"); C1:D9)
Sample data
A B C D
01 male young Comment 1 Comment 2
02 male old Comment 3 Comment 4
03 female young Comment 5 Comment 6
04 female old Comment 7 Comment 8
05 male young Comment 9 Comment A
Results in
* Comment 1
* Comment 2
* Comment 9
* Comment A
For Google: This shall also be found as VERKETTENWENN()
对于谷歌:这也应该被发现为VERKETTENWENN()
#1
2
The problem was because formula:
问题是因为公式:
=CONCATIF((A1:A9=C1)*(B1:B9=D1); E1:E9)
need to be called by pressing CTRL+SHIFT+ENTER
需要通过按CTRL + SHIFT + ENTER来调用
#2
0
For the sake of completeness, here's the complete Excel VBA Macro to concatenate strings from a range (may have multiple string columns), if criteria in other columns are matched.
为了完整起见,这里是完整的Excel VBA宏,用于连接范围中的字符串(可能有多个字符串列),如果其他列中的条件匹配。
' **********************************************************************
' Modul: Modul1 Typ: Allgemeines Modul
' **********************************************************************
Option Explicit
Public Function CONCATIF(Kriterium, Inhalte)
Dim mydic As Object
Dim L As Long
Dim C As Long
Dim N As Long
Dim cols As Long
Set mydic = CreateObject("Scripting.Dictionary")
cols = Inhalte.Columns.Count
N = 1
For L = 1 To UBound(Kriterium)
If Kriterium(L, 1) = 1 Then
For C = 1 To cols
If Not IsEmpty(Inhalte(L, C)) Then
mydic(N) = "* " & Inhalte(L, C)
N = N + 1
End If
Next
End If
Next
CONCATIF= Join(mydic.items, vbCrLf)
End Function
Use as follows - and don't forget to enter by CTRL+SHIFT+ENTER
使用如下 - 并且不要忘记通过CTRL + SHIFT + ENTER输入
=CONCATIF((A1:A:9="male")*(B1:B9="young"); C1:D9)
Sample data
A B C D
01 male young Comment 1 Comment 2
02 male old Comment 3 Comment 4
03 female young Comment 5 Comment 6
04 female old Comment 7 Comment 8
05 male young Comment 9 Comment A
Results in
* Comment 1
* Comment 2
* Comment 9
* Comment A
For Google: This shall also be found as VERKETTENWENN()
对于谷歌:这也应该被发现为VERKETTENWENN()