Java将文件读入ArrayList？

How do you read the contents of a file into an ArrayList<String> in Java?

如何在Java中将文件内容读入ArrayList ？

Here are the file contents:

这是文件内容：

cat
house
dog
.
.
.

Just read each word into the ArrayList.

只需将每个单词读入ArrayList即可。

11 个解决方案

#1

This java code reads in each word and puts it into the ArrayList:

这个java代码读入每个单词并将其放入ArrayList：

Scanner s = new Scanner(new File("filepath"));
ArrayList<String> list = new ArrayList<String>();
while (s.hasNext()){
    list.add(s.next());
}
s.close();

Use s.hasNextLine() and s.nextLine() if you want to read in line by line instead of word by word.

如果要逐行而不是逐字读取，请使用s.hasNextLine（）和s.nextLine（）。

#2

A one-liner with commons-io:

与commons-io的单行：

List<String> lines = FileUtils.readLines(new File("/path/to/file.txt"), "utf-8");

The same with guava:

与番石榴一样：

List<String> lines = 
     Files.readLines(new File("/path/to/file.txt"), Charset.forName("utf-8"));

#3

You can use:

您可以使用：

List<String> list = Files.readAllLines(new File("input.txt").toPath(), Charset.defaultCharset() );

Source: Java API 7.0

来源：Java API 7.0

#4

In Java 8 you could use streams and Files.lines:

在Java 8中，您可以使用stream和Files.lines：

List<String> list = null;
try (Stream<String> lines = Files.lines(myPathToTheFile))) {
    list = lines.collect(Collectors.toList());
} catch (IOException e) {
    LOGGER.error("Failed to load file.", e);
}

Or as a function including loading the file from the file system:

或者作为一个函数，包括从文件系统加载文件：

private List<String> loadFile() {
    List<String> list = null;
    URI uri = null;

    try {
        uri = ClassLoader.getSystemResource("example.txt").toURI();
    } catch (URISyntaxException e) {
        LOGGER.error("Failed to load file.", e);
    }

    try (Stream<String> lines = Files.lines(Paths.get(uri))) {
        list = lines.collect(Collectors.toList());
    } catch (IOException e) {
        LOGGER.error("Failed to load file.", e);
    }
    return list;
}

#5

Simplest form I ever found is...

我发现的最简单的形式是......

List<String> lines = Files.readAllLines(Paths.get("/path/to/file.txt"));

#6

List<String> words = new ArrayList<String>();
BufferedReader reader = new BufferedReader(new FileReader("words.txt"));
String line;
while ((line = reader.readLine()) != null) {
    words.add(line);
}
reader.close();

#7

You can for example do this in this way (full code with exceptions handlig):

例如，您可以这样做（带有异常handlig的完整代码）：

BufferedReader in = null;
List<String> myList = new ArrayList<String>();
try {   
    in = new BufferedReader(new FileReader("myfile.txt"));
    String str;
    while ((str = in.readLine()) != null) {
        myList.add(str);
    }
} catch (FileNotFoundException e) {
    e.printStackTrace();
} catch (IOException e) {
    e.printStackTrace();
} finally {
    if (in != null) {
        in.close();
    }
}

#8

//CS124 HW6 Wikipedia Relation Extraction
//Alan Joyce (ajoyce)
public List<String> addWives(String fileName) {
    List<String> wives = new ArrayList<String>();
    try {
        BufferedReader input = new BufferedReader(new FileReader(fileName));
        // for each line
        for(String line = input.readLine(); line != null; line = input.readLine()) {
            wives.add(line);
        }
        input.close();
    } catch(IOException e) {
        e.printStackTrace();
        System.exit(1);
        return null;
    }
    return wives;
}

#9

Here's a solution that has worked pretty well for me:

这是一个对我来说非常好的解决方案：

List<String> lines = Arrays.asList(
    new Scanner(new File(file)).useDelimiter("\\Z").next().split("\\r?\\n")
);

If you don't want empty lines, you can also do:

如果你不想要空行，你也可以这样做：

List<String> lines = Arrays.asList(
    new Scanner(new File(file)).useDelimiter("\\Z").next().split("[\\r\\n]+")
);

#10

Here is an entire program example:

这是一个完整的程序示例：

import java.io.File;
import java.io.FileNotFoundException;
import java.util.ArrayList;
import java.util.Scanner;

public class X {
    public static void main(String[] args) {
    File f = new File("D:/projects/eric/eclipseworkspace/testing2/usernames.txt");
        try{
            ArrayList<String> lines = get_arraylist_from_file(f);
            for(int x = 0; x < lines.size(); x++){
                System.out.println(lines.get(x));
            }
        }
        catch(Exception e){
            e.printStackTrace();
        }
        System.out.println("done");

    }
    public static ArrayList<String> get_arraylist_from_file(File f) 
        throws FileNotFoundException {
        Scanner s;
        ArrayList<String> list = new ArrayList<String>();
        s = new Scanner(f);
        while (s.hasNext()) {
            list.add(s.next());
        }
        s.close();
        return list;
    }
}

#11

Add this code to sort the data in text file. Collections.sort(list);

添加此代码以对文本文件中的数据进行排序。 Collections.sort（名单）;