I'm trying to write a kernel module which writes some data to a proc file. I'm trying to write something like 5000 characters but when I say $>cat /proc/myentry I can read only 1000 characters.
我正在尝试编写一个内核模块,它将一些数据写入proc文件。我正在尝试写5000个字符,但当我说$> cat / proc / myentry时我只能读1000个字符。
int procfile_read(char *buffer, char **buffer_location, off_t offset, int buffer_length, int *eof, void *data){
int ret;
static char my_buffer[4096];
if (offset > 0) {
ret = 0;
} else {
ret = sprintf(my_buffer, LARGE STRING HERE);
}
*buffer_location=my_buffer;
return ret;
}
This is my code. Thanks in advance.
这是我的代码。提前致谢。
2 个解决方案
#1
3
I had exactly this problem.
我有这个问题。
One issue in the original post, the if (offset>0)
is used many times in examples of small proc files. The read is called multiple times until we return a 0 to indicate that there is no more data. So the if (offset>0)
means we return (length of the buffer) as 0.
原始帖子中的一个问题是if(offset> 0)在小proc文件的示例中多次使用。多次调用读取,直到我们返回0表示没有更多数据。所以if(offset> 0)意味着我们返回(缓冲区的长度)为0。
There are 3 ways to return data with this function. Look at the source code comments, line 75 onwards :
使用此功能有3种方法可以返回数据。查看源代码注释,第75行:
For large files (method 2 from comments), I did the following :-
对于大文件(评论中的方法2),我做了以下内容: -
- For each lump of your large data, copy 'buffer_length' of data to 'buffer'.
- Set '*start' (or in your case *buffer_location) to 'buffer'.
- return the amount of data you wrote (typically 'buffer_length')
对于每个大数据块,将'buffer_length'数据复制到'buffer'。
将'* start'(或在您的情况下为* buffer_location)设置为'buffer'。
返回你写的数据量(通常是'buffer_length')
Finally, all data will be written and you return 0.
最后,所有数据都将被写入并返回0。
This worked for me with several Meg of data.
这对我来说有几个Meg数据。
#2
3
I am not a kernel expert, but in linux-3.1.6/fs/proc/task_mmu.c
I see some code like
我不是内核专家,但在linux-3.1.6 / fs / proc / task_mmu.c中我看到了一些代码
seq_printf(m,
"VmPeak:\t%8lu kB\n"
"VmSize:\t%8lu kB\n"
"VmLck:\t%8lu kB\n"
"VmHWM:\t%8lu kB\n"
"VmRSS:\t%8lu kB\n"
"VmData:\t%8lu kB\n"
"VmStk:\t%8lu kB\n"
so this suggests that you might want to use seq_printf
not sprintf
.... The m
is a struct seq_file *
pointer.
所以这表明你可能想要使用seq_printf而不是sprintf .... m是一个struct seq_file *指针。
As a general rule, you'll learn a lot by studying the free software source code which you are extending. In your case, it is the Linux kernel source code
作为一般规则,通过研究您正在扩展的免费软件源代码,您将学到很多东西。在您的情况下,它是Linux内核源代码
#1
3
I had exactly this problem.
我有这个问题。
One issue in the original post, the if (offset>0)
is used many times in examples of small proc files. The read is called multiple times until we return a 0 to indicate that there is no more data. So the if (offset>0)
means we return (length of the buffer) as 0.
原始帖子中的一个问题是if(offset> 0)在小proc文件的示例中多次使用。多次调用读取,直到我们返回0表示没有更多数据。所以if(offset> 0)意味着我们返回(缓冲区的长度)为0。
There are 3 ways to return data with this function. Look at the source code comments, line 75 onwards :
使用此功能有3种方法可以返回数据。查看源代码注释,第75行:
For large files (method 2 from comments), I did the following :-
对于大文件(评论中的方法2),我做了以下内容: -
- For each lump of your large data, copy 'buffer_length' of data to 'buffer'.
- Set '*start' (or in your case *buffer_location) to 'buffer'.
- return the amount of data you wrote (typically 'buffer_length')
对于每个大数据块,将'buffer_length'数据复制到'buffer'。
将'* start'(或在您的情况下为* buffer_location)设置为'buffer'。
返回你写的数据量(通常是'buffer_length')
Finally, all data will be written and you return 0.
最后,所有数据都将被写入并返回0。
This worked for me with several Meg of data.
这对我来说有几个Meg数据。
#2
3
I am not a kernel expert, but in linux-3.1.6/fs/proc/task_mmu.c
I see some code like
我不是内核专家,但在linux-3.1.6 / fs / proc / task_mmu.c中我看到了一些代码
seq_printf(m,
"VmPeak:\t%8lu kB\n"
"VmSize:\t%8lu kB\n"
"VmLck:\t%8lu kB\n"
"VmHWM:\t%8lu kB\n"
"VmRSS:\t%8lu kB\n"
"VmData:\t%8lu kB\n"
"VmStk:\t%8lu kB\n"
so this suggests that you might want to use seq_printf
not sprintf
.... The m
is a struct seq_file *
pointer.
所以这表明你可能想要使用seq_printf而不是sprintf .... m是一个struct seq_file *指针。
As a general rule, you'll learn a lot by studying the free software source code which you are extending. In your case, it is the Linux kernel source code
作为一般规则,通过研究您正在扩展的免费软件源代码,您将学到很多东西。在您的情况下,它是Linux内核源代码