I've been searching SO (and the rest of the Internet) for the answer, but I can't seem to find a solution for selecting an XML node based on an attribute.
This is my XML below this is for placing productcategoryid
from a REST service XML
我一直在搜索SO(以及Internet的其他部分)来寻找答案,但我似乎找不到基于属性选择XML节点的解决方案。下面是我的XML,用于从REST服务XML中放置productcategoryid
<lst name="responseHeader">
<int name="status">0</int>
<int name="QTime">0</int>
<lst name="params">
<str name="q">*:*</str>
<str name="indent">true</str>
<str name="wt">xml</str>
</lst>
</lst>
<result name="response" numFound="5429" start="0">
<doc>
<int name="idProductCategory">2</int>
<str name="categoryname">Live Animals</str>
<int name="categoryLevel">2</int>
<str name="bestOfferEnabled">false</str>
<str name="leafCategory">true</str>
<int name="parentCategoryId">1</int>
<long name="_version_">1535190804282212352</long>
</doc>
</result>
</response>
I need to get the element of idProductCategory
, i.e. 2
, through VBA code, but I can't make it from below code.
我需要通过VBA代码获得idProductCategory的元素,即2,但是我不能从下面的代码中得到它。
Sub getProductCategory(prodCatName As String)
Dim result1 As String
Dim result As String
Dim myURL As String
Dim winHttpReq As Object
Set winHttpReq = CreateObject("WinHttp.WinHttpRequest.5.1")
myURL = "http://localhost:8080/solr/category/select?q=" & prodCatName & "&wt=json"
MsgBox myURL
winHttpReq.Open "GET", myURL, False
winHttpReq.Send
MsgBox winHttpReq.responseText
Dim doc_XML As DOMDocument60
Set doc_XML = New DOMDocument60
result = winHttpReq.responseText
doc_XML.Load result
Set List = doc_XML.documentElement.childNodes
For Each sub_list In List
If sub_list.Attributes(0).Text = "response" Then
For Each Node In sub_list.childNodes(0).childNodes
If Node.Attributes(0).Text = "idProductCategory" Then
result1 = Node.nodeTypedValue
End If
Next Node
End If
Next sub_list
End Sub
So please help me, I'm struggling on this I need to get element value by attribute name from this above XML and place it in a particular cell in Excel.
请帮助我,我在这个问题上很纠结我需要从上面的XML中获取元素值并将它放在Excel中的一个特定单元格中。
2 个解决方案
#1
1
This code works, it is less elegant than the query you tried to use, but IMO it is easier to understand, as working with xml can be a bit confusing.
这段代码是有效的,它没有您尝试使用的查询那么优雅,但是在我看来,它更容易理解,因为使用xml可能有点令人困惑。
Sub prueba2()
Dim doc_XML As DOMDocument60
Set doc_XML = New DOMDocument60
data = winHttpReq.responseText
doc_XML.Load data
Set List = doc_XML.DocumentElement.ChildNodes
For Each sub_list In List
If sub_list.Attributes(0).Text = "response" Then
For Each Node In sub_list.ChildNodes(0).ChildNodes
If Node.Attributes(0).Text = "idProductCategory" Then
result = Node.nodeTypedValue
End If
Next Node
End If
Next sub_list
End Sub
The xml example used was:
使用的xml示例是:
<response>
<lst name="responseHeader">
<int name="status">0</int>
<int name="QTime">0</int>
<lst name="params">
<str name="q">*:*</str>
<str name="indent">true</str>
<str name="wt">xml</str>
</lst>
</lst>
<result name="response" numFound="5429" start="0">
<doc>
<int name="idProductCategory">2</int>
<str name="categoryname">Live Animals</str>
<int name="categoryLevel">2</int>
<str name="bestOfferEnabled">false</str>
<str name="leafCategory">true</str>
<int name="parentCategoryId">1</int>
<long name="_version_">1535190804282212352</long>
</doc>
</result>
</response>
#2
0
Using SelectSingleNode
the code could look like this. HTH
使用SelectSingleNode,代码可以像这样。HTH
' Add reference to Microsoft XML v6.0 library
Public Const XML As String = _
"<response>" & _
"<lst name='responseHeader'>" & _
"<int name='status'>0</int>" & _
"<int name='QTime'>0</int>" & _
"<lst name='params'>" & _
"<str name='q'>*:*</str>" & _
"<str name='indent'>true</str>" & _
"<str name='wt'>xml</str>" & _
"</lst>" & _
"</lst>" & _
"<result name='response' numFound='5429' start='0'>" & _
"<doc>" & _
"<int name='idProductCategory'>2</int>" & _
"<str name='categoryname'>Live Animals</str>" & _
"<int name='categoryLevel'>2</int>" & _
"<str name='bestOfferEnabled'>false</str>" & _
"<str name='leafCategory'>true</str>" & _
"<int name='parentCategoryId'>1</int>" & _
"<long name='_version_'>1535190804282212352</long>" & _
"</doc>" & _
"</result>" & _
"</response>"
Sub test()
Dim xmlDocument As MSXML2.DOMDocument60
Set xmlDocument = New DOMDocument60
If Not xmlDocument.LoadXML(XML) Then
Err.Raise xmlDocument.parseError.ErrorCode, , xmlDocument.parseError.reason
End If
Dim nodeIdProductCategory As IXMLDOMNode
Set nodeIdProductCategory = xmlDocument.SelectSingleNode("/response/result/doc/int[@name='idProductCategory']")
If Not nodeIdProductCategory Is Nothing Then
MsgBox nodeIdProductCategory.text
Else
MsgBox "Node witd name 'idProductCategory' was not found."
End If
End Sub
#1
1
This code works, it is less elegant than the query you tried to use, but IMO it is easier to understand, as working with xml can be a bit confusing.
这段代码是有效的,它没有您尝试使用的查询那么优雅,但是在我看来,它更容易理解,因为使用xml可能有点令人困惑。
Sub prueba2()
Dim doc_XML As DOMDocument60
Set doc_XML = New DOMDocument60
data = winHttpReq.responseText
doc_XML.Load data
Set List = doc_XML.DocumentElement.ChildNodes
For Each sub_list In List
If sub_list.Attributes(0).Text = "response" Then
For Each Node In sub_list.ChildNodes(0).ChildNodes
If Node.Attributes(0).Text = "idProductCategory" Then
result = Node.nodeTypedValue
End If
Next Node
End If
Next sub_list
End Sub
The xml example used was:
使用的xml示例是:
<response>
<lst name="responseHeader">
<int name="status">0</int>
<int name="QTime">0</int>
<lst name="params">
<str name="q">*:*</str>
<str name="indent">true</str>
<str name="wt">xml</str>
</lst>
</lst>
<result name="response" numFound="5429" start="0">
<doc>
<int name="idProductCategory">2</int>
<str name="categoryname">Live Animals</str>
<int name="categoryLevel">2</int>
<str name="bestOfferEnabled">false</str>
<str name="leafCategory">true</str>
<int name="parentCategoryId">1</int>
<long name="_version_">1535190804282212352</long>
</doc>
</result>
</response>
#2
0
Using SelectSingleNode
the code could look like this. HTH
使用SelectSingleNode,代码可以像这样。HTH
' Add reference to Microsoft XML v6.0 library
Public Const XML As String = _
"<response>" & _
"<lst name='responseHeader'>" & _
"<int name='status'>0</int>" & _
"<int name='QTime'>0</int>" & _
"<lst name='params'>" & _
"<str name='q'>*:*</str>" & _
"<str name='indent'>true</str>" & _
"<str name='wt'>xml</str>" & _
"</lst>" & _
"</lst>" & _
"<result name='response' numFound='5429' start='0'>" & _
"<doc>" & _
"<int name='idProductCategory'>2</int>" & _
"<str name='categoryname'>Live Animals</str>" & _
"<int name='categoryLevel'>2</int>" & _
"<str name='bestOfferEnabled'>false</str>" & _
"<str name='leafCategory'>true</str>" & _
"<int name='parentCategoryId'>1</int>" & _
"<long name='_version_'>1535190804282212352</long>" & _
"</doc>" & _
"</result>" & _
"</response>"
Sub test()
Dim xmlDocument As MSXML2.DOMDocument60
Set xmlDocument = New DOMDocument60
If Not xmlDocument.LoadXML(XML) Then
Err.Raise xmlDocument.parseError.ErrorCode, , xmlDocument.parseError.reason
End If
Dim nodeIdProductCategory As IXMLDOMNode
Set nodeIdProductCategory = xmlDocument.SelectSingleNode("/response/result/doc/int[@name='idProductCategory']")
If Not nodeIdProductCategory Is Nothing Then
MsgBox nodeIdProductCategory.text
Else
MsgBox "Node witd name 'idProductCategory' was not found."
End If
End Sub