SQL实现LeetCode(182.重复的邮箱)

[LeetCode] 182.Duplicate Emails 重复的邮箱

Write a SQL query to find all duplicate emails in a table named Person.

+----+---------+
| Id | Email   |
+----+---------+
| 1  | [e-mail] |
| 2  | [e-mail] |
| 3  | [e-mail] |
+----+---------+

For example, your query should return the following for the above table:

+---------+
| Email   |
+---------+
| [e-mail] |
+---------+

Note: All emails are in lowercase.

这道题让我们求重复的邮箱，那么最直接的方法就是用Group by...Having Count(*)...的固定搭配来做，代码如下：

解法一：

SELECT Email FROM Person GROUP BY Email
HAVING COUNT(*) > 1;

我们还可以用内交来做，用Email来内交两个表，然后返回Id不同的行，则说明两个不同的人使用了相同的邮箱：

解法二：

SELECT DISTINCT p1.Email FROM Person p1
JOIN Person p2 ON p1.Email = p2.Email
WHERE p1.Id <> p2.Id;

参考资料：

https://leetcode.com/discuss/53206/a-solution-using-a-group-by-and-another-one-using-a-self-join

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原文链接：https://www.cnblogs.com/grandyang/p/5361967.html