I'm currently using the substr() function which works fine for characters written in english. But when I apply that to characters written in greek, the text is cut with a strange character (a questionmark inside a diamond shape) appearing before the 3 fullstops (...). Below is the code, thanks:
我目前正在使用substr（）函数，该函数适用于用英语编写的字符。但是当我将它应用于用希腊语写的字符时，文本会被切割成一个奇怪的字符（钻石形状内的问号）出现在3个完整停止之前（...）。以下是代码，谢谢：
$string //a varchar string written in greek and called from the database
if (strlen($string) > 200) {
echo substr($string, 0, 200).'...';
}
1 个解决方案
#1
1
Use multibyte functions like so:
使用多字节函数，如下所示：
mb_internal_encoding( "UTF-8" );
if( mb_strlen( $string ) > 200 ) {
echo mb_substr( $string, 0, 200 ) . "...";
}
The normal functions work on bytes and don't have any character awareness like you are expecting from them. Text using common english characters in UTF-8 are all 1 byte per character, so the normal functions accidentally work for them.
普通函数对字节起作用，并且没有像你期望的那样具有任何字符感知。使用UTF-8中常见英文字符的文本每个字符都是1个字节，因此正常功能会意外地为它们工作。
#1
1
Use multibyte functions like so:
使用多字节函数，如下所示：
mb_internal_encoding( "UTF-8" );
if( mb_strlen( $string ) > 200 ) {
echo mb_substr( $string, 0, 200 ) . "...";
}
The normal functions work on bytes and don't have any character awareness like you are expecting from them. Text using common english characters in UTF-8 are all 1 byte per character, so the normal functions accidentally work for them.
普通函数对字节起作用，并且没有像你期望的那样具有任何字符感知。使用UTF-8中常见英文字符的文本每个字符都是1个字节，因此正常功能会意外地为它们工作。