下面是小编给大家分享的一个使用java写单链表,有问题欢迎给我留言哦。
首先定义一个Node类
1
2
3
4
5
6
7
8
9
10
11
12
|
public class Node {
protected Node next; //指针域
public int data; //数据域
public Node( int data) {
this . data = data;
}
//显示此节点
public void display() {
System. out.print( data + " " );
}
}
|
接下来定义一个单链表,并实现相关方法:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
|
public class LinkList {
public Node first; // 定义一个头结点
private int pos = 0 ; // 节点的位置
public LinkList() {
this .first = null ;
}
// 插入一个头节点
public void addFirstNode( int data) {
Node node = new Node(data);
node.next = first;
first = node;
}
// 删除一个头结点,并返回头结点
public Node deleteFirstNode() {
Node tempNode = first;
first = tempNode.next;
return tempNode;
}
// 在任意位置插入节点 在index的后面插入
public void add( int index, int data) {
Node node = new Node(data);
Node current = first;
Node previous = first;
while (pos != index) {
previous = current;
current = current.next;
pos++;
}
node.next = current;
previous.next = node;
pos = 0 ;
}
// 删除任意位置的节点
public Node deleteByPos( int index) {
Node current = first;
Node previous = first;
while (pos != index) {
pos++;
previous = current;
current = current.next;
}
if (current == first) {
first = first.next;
} else {
pos = 0 ;
previous.next = current.next;
}
return current;
}
// 根据节点的data删除节点(仅仅删除第一个)
public Node deleteByData( int data) {
Node current = first;
Node previous = first; // 记住上一个节点
while (current.data != data) {
if (current.next == null ) {
return null ;
}
previous = current;
current = current.next;
}
if (current == first) {
first = first.next;
} else {
previous.next = current.next;
}
return current;
}
// 显示出所有的节点信息
public void displayAllNodes() {
Node current = first;
while (current != null ) {
current.display();
current = current.next;
}
System.out.println();
}
// 根据位置查找节点信息
public Node findByPos( int index) {
Node current = first;
if (pos != index) {
current = current.next;
pos++;
}
return current;
}
// 根据数据查找节点信息
public Node findByData( int data) {
Node current = first;
while (current.data != data) {
if (current.next == null )
return null ;
current = current.next;
}
return current;
}
}
|
最后我们可以通过测试类来做相关测试:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
|
public class TestLinkList {
public static void main(String[] args) {
LinkList linkList = new LinkList();
linkList.addFirstNode( 20 );
linkList.addFirstNode( 21 );
linkList.addFirstNode( 19 );
//print19,21,20
linkList.add( 1 , 22 ); //print19,22,21,20
linkList.add( 2 , 23 ); //print19,22,23,21,20
linkList.add( 3 , 99 ); //print19,22,23,99,21,20
//调用此方法会print 19,22,23,99,21,20
linkList.displayAllNodes();
}
}
|
至此,对单链表的操作就笔记到这里了。
以上所述是小编给大家介绍的Java单链表的实现代码,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对服务器之家网站的支持!
原文链接:http://www.cnblogs.com/_popc/p/4025684.html