从用户那里获取字符串，然后从屏幕上删除它。

This simple program acquires characters from the users (till a newline character) and prints them:

这个简单的程序从用户那里获得字符(直到换行符)并打印出来:

#include <stdio.h>

int main()
{
    char local_message[200];
    scanf("%[^\n]%*c", local_message);
    printf("Your message is %s\n", local_message);

    return 0;
}

But when I run it, the characters I typed stay printed into the screen:

但是当我运行它时，我输入的字符会被打印到屏幕上:

Hello World!
Your message is Hello World!

The characters I typed were "Hello World!\n". I would like that when I press "Enter" to create the newline \n character, my message disappears from the screen (while being stored into the char array), so that I can print (and format) it with the following printf.

我输入的字符是“Hello World!\n”。我希望当我按下“Enter”来创建newline \n字符时，我的消息将从屏幕上消失(同时存储到char数组中)，以便我可以用以下printf打印(并格式化)它。

The OS is Linux.

Linux操作系统。

Is it possible? How?

是可能的吗?如何?

1 个解决方案

#1

You may be able to do this with terminal escape codes.

您可以使用终端转义代码来实现这一点。

#include <stdio.h>

int main ( ) {
    char local_message[200];

    scanf("%199[^\n]%*c", local_message);
    printf ( "\033[0A");//move cursor up one line
    printf ( "\033[2K");//clear line
    printf("\nYour message is %s\n", local_message);

    return 0;
}

EDIT:
This will give a little more control and erase inputs more than one line.

编辑:这将提供更多的控制，并删除多行输入。

#include <stdio.h>

int main ( ) {
    char local_message[200];

    printf ( "\033[2J");//clear screen and move cursor to upper left corner
    printf ( "\033[8;H");//move cursor to line 8
    printf("Enter Your message\n");
    scanf("%199[^\n]%*c", local_message);
    printf ( "\033[9;H");//move cursor to line 9
    printf ( "\033[J");//clear screen from line to end
    printf ( "\033[12;H");//move cursor to line 12
    printf("\nYour message is %s\n", local_message);

    return 0;
}

#1