数据步骤/SQL Join/Merge/Union 2数据集/表并删除相同的行/观察

For example, I have 2 tables like this

例如，我有两个这样的表。

data have;
input name $ status $;
datalines;
A    a
B    b
C    c
;;;;
run;

2nd table:

表2:

data addon;
input name $ status $;
datalines;
A    a
C    f
D    d
E    e
F    f
B    z
;;;;
run;

How do I get the result like below:

如何得到如下结果:

B    b
C    c
C    f
D    d
E    e
F    f
B    z

The row A - a is the same from 2 tables so it got removed. I'm trying to use left join but the result is not right. Please help and thanks in advance. I'm really appreciated it.

A - A的行从两个表中是一样的，所以它被删除了。我试着用左连接，但结果是不对的。请提前帮助和感谢。我很欣赏它。

5 个解决方案

#1

Another way

另一种方式

data have;
 input name $ status $;
 datalines;
A    a
B    b
C    c
;;;;
run;

data addon;
 input name $ status $;
datalines;
A    a
C    f
D    d
E    e
F    f
B    z
;;;;
run;

Data Together;
 Set have addon;
 /* If the data sets were already sorted */
 /* By Name Status;                      */
/*  Then skip the Proc Sort              */
Run;

Proc sort data=together;
 by name status;
Run;

Data final;
 Set Together;
 by name status;
 if first.status and last.status;
Run;

#2

Try this:

试试这个:

  SELECT COALESCE(table1.input, table2.input) AS input
         , COALESCE(table1.status, table2.status) AS status
    FROM table1
         FULL OUTER JOIN table2 ON table1.input = table2.input
         AND table1.status = table2.status
   WHERE (table1.input IS NULL OR table2.input IS NULL)
ORDER BY 1

Output :

输出:

INPUT STATUS
----- ------
B     b      
B     z      
C     f      
C     c      
D     d      
E     e      
F     f      

#3

Don't have time to test this, but this is approximately right. Won't work in SQLFiddle since MySQL doesn't support except.

没有时间进行测试，但这是大致正确的。不会在SQLFiddle工作，因为MySQL不支持。

select * from (
  select * from have union select * from addon)
except
( select * from have, addon 
   where have.status=addon.status and have.name=addon.name)

#4

SELECT t1.name,t1.status
FROM 
  (
    SELECT name,status
    FROM have
    UNION ALL
    SELECT name,status
    FROM addon
  ) as t1
JOIN have t2 ON t1.name!=t2.name AND t1.status!=t2.status
JOIN addon t3 ON t2.name=t3.name AND t2.status=t3.status

I created an SQL fiddle for you.

我为你创建了一个SQL小提琴。

#5

data have;
input name $ status $;
datalines;
A    a
B    b
C    c
;;;;
run;

2nd table:

表2:

data addon;
input name $ status $;
datalines;
A    a
C    f
D    d
E    e
F    f
B    z
;;;;
run;

How do I get the result like below:

如何得到如下结果:

B    b
C    c
C    f
D    d
E    e
F    f
B    z

Simple Use merge statement. Sort the datasets using the keys before this step

简单使用merge语句。在此步骤之前，使用键对数据集进行排序

DATA RESULT;
KEEP H.NAME A.STATUS;
MERGE HAVE(IN = H) ADDON (IN = A);
BY NAME;
RUN;