关于程序相关的
- 您可以反复玩游戏，直到选择停止为止。
- 该程序跟踪获胜情况。
- 大小写无关紧要（即ROCK与Rock相同）。
- 如果您输入的内容无效，程序会一直提示您，直到您输入有效的内容。
对项目进行编码的步骤：
- 创建一个简单的单轮游戏版本，我们不执行正确的输入。
- 如果输入了无效的内容，则添加while循环可重新提示用户输入选择。
- 使用while循环让用户反复播放，并使用变量来跟踪得分。
程序代码
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import random
input("Welcome to Rock, Paper, Scissors! Press Enter to start.")
print()
user_wins = 0
computer_wins = 0
choices = ["rock", "paper", "scissors"]
while True:
random_index = random.randint(0,2)
cpu_choice = choices[random_index]
user_choice = input("Rock, Paper, or Scissors? ").lower()
while user_choice not in choices:
user_choice = input("That is not a valid choice. Please try again: ").lower()
print()
print("Your choice:", user_choice)
print("Computer's choice:", cpu_choice)
print()
if user_choice == 'rock':
if cpu_choice == 'rock':
print("It's a tie!")
elif cpu_choice == 'scissors':
print("You win!")
user_wins+=1
elif cpu_choice == 'paper':
print("You lose!")
computer_wins+=1
elif user_choice == 'paper':
if cpu_choice == 'paper':
print("It's a tie!")
elif cpu_choice == 'rock':
print("You win!")
user_wins+=1
elif cpu_choice == 'scissors':
print("You lose!")
computer_wins+=1
elif user_choice == 'scissors':
if cpu_choice == 'scissors':
print("It's a tie!")
elif cpu_choice == 'paper':
print("You win!")
user_wins+=1
elif cpu_choice == 'rock':
print("You lose!")
computer_wins+=1
print()
print("You have "+str(user_wins)+" wins")
print("The computer has "+str(computer_wins)+" wins")
print()
repeat = input("Play again? (Y/N) ").lower()
while repeat not in ['y', 'n']:
repeat = input("That is not a valid choice. Please try again: ").lower()
if repeat == 'n':
break
print("\n----------------------------\n")
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运行效果：
以上就是Python制作简单的剪刀石头布游戏的详细内容，更多关于Python 剪刀石头布游戏的资料请关注服务器之家其它相关文章！
原文链接：https://junilearning.com/blog/coding-projects/make-rock-paper-scissors-in-python