A small question hopefully with a simple answer, I am using jQuery draggable and droppable to place items into a dock. Using the below code for the drop.
一个小问题希望通过一个简单的答案，我使用jQuery draggable和droppable将项目放入Dock。使用下面的代码进行删除。
$("#dock").droppable({
drop: function(event, ui) {
//Do something to the element dropped?!?
}
});
However I couldn't find a way to get what element was actually dropped, so I can do something do it. Is this possible?
但是我找不到一种方法来获取实际丢弃的元素，所以我可以做一些事情。这可能吗？
1 个解决方案
#1
91
From the drop event documentation:
从drop事件文档中：
This event is triggered when an accepted draggable is dropped 'over' (within the tolerance of) this droppable. In the callback, $(this) represents the droppable the draggable is dropped on. ui.draggable represents the draggable.
当可接受的拖动器被丢弃（在容差范围内）此可放置时，将触发此事件。在回调中，$（this）表示draggable被丢弃的droppable。 ui.draggable代表可拖动的。
So:
所以：
$("#dock").droppable({
drop: function(event, ui) {
// do something with the dock
$(this).doSomething();
// do something with the draggable item
$(ui.draggable).doSomething();
}
});
#1
91
From the drop event documentation:
从drop事件文档中：
This event is triggered when an accepted draggable is dropped 'over' (within the tolerance of) this droppable. In the callback, $(this) represents the droppable the draggable is dropped on. ui.draggable represents the draggable.
当可接受的拖动器被丢弃（在容差范围内）此可放置时，将触发此事件。在回调中，$（this）表示draggable被丢弃的droppable。 ui.draggable代表可拖动的。
So:
所以：
$("#dock").droppable({
drop: function(event, ui) {
// do something with the dock
$(this).doSomething();
// do something with the draggable item
$(ui.draggable).doSomething();
}
});