Problem Description
There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can’t move on red tiles, he can move only on black tiles.
Write a program to count the number of black tiles which he can reach by repeating the moves described above.
Input
The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.
There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.
‘.’ - a black tile
‘#’ - a red tile
‘@’ - a man on a black tile(appears exactly once in a data set)
The end of the input is indicated by a line consisting of two zeros.
Output
For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).
Sample Input
6 9
....#.
.....#
......
......
......
......
......
#@...#
.#..#.
11 9
.#.........
.#.#######.
.#.#.....#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#.......#.
.#########.
...........
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
###.###
...@...
###.###
..#.#..
..#.#..
0 0
Sample Output
45
59
6
13#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
char d[30][30];
bool vis[30][30];
int str[4][2]={{0,1},{1,0},{0,-1},{-1,0}};
int n,m,s;
using namespace std;
void dfs(int x,int y){
for(int i=0;i<4;i++){
int xx=x+str[i][0];
int yy=y+str[i][1];
if(xx>=0&&yy>=0&&xx<m&&yy<n&&d[xx][yy]=='.'&&vis[xx][yy]==0){
s++;
// printf("%d\n",s);
vis[xx][yy]=1;
dfs(xx,yy);
}
if(i==3)
return ;
}
}
int main()
{
int a,b;
while(~scanf("%d%d",&n,&m)&&(n||m)){
for(int i=0;i<m;i++){
scanf("%s",&d[i]);
for(int j=0;j<n;j++){
if(d[i][j]=='@'){
a=i;
b=j;
}
}
}
memset(vis,0,sizeof(vis));
s=1;
d[a][b]='#';
dfs(a,b);
printf("%d\n",s);
}
return 0;
}