执行函数时放入python解释器

时间:2022-12-04 20:24:04

i have a python module with a function:

我有一个功能的python模块:

def do_stuff(param1 = 'a'):
    if type(param1) == int:
        # enter python interpreter here
        do_something()
    else:
        do_something_else()

is there a way to drop into the command line interpreter where i have the comment? so that if i run the following in python:

有没有办法进入命令行解释器,我有评论?所以,如果我在python中运行以下内容:

>>> import my_module
>>> do_stuff(1)

i get my next prompt in the scope and context of where i have the comment in do_stuff()?

我在do_stuff()的评论范围和上下文中得到了我的下一个提示?

3 个解决方案

#1


47  

Inserting

插入

import pdb; pdb.set_trace()

will enter the python debugger at that point

此时将进入python调试器

See here: http://docs.python.org/library/pdb.html

见这里:http://docs.python.org/library/pdb.html

#2


123  

If you want a standard interactive prompt (instead of the debugger, as shown by prestomation), you can do this:

如果你想要一个标准的交互式提示(而不是调试器,如prestomation所示),你可以这样做:

import code
code.interact(local=locals())

See: the code module.

请参阅:代码模块。

If you have IPython installed, and want an IPython shell instead, you can do this for IPython >= 0.11:

如果你安装了IPython,并且想要一个IPython shell,你可以为IPython> = 0.11执行此操作:

import IPython; IPython.embed()

or for older versions:

或旧版本:

from IPython.Shell import IPShellEmbed
ipshell = IPShellEmbed()
ipshell(local_ns=locals())

#3


18  

If you want a default Python interpreter, you can do

如果你想要一个默认的Python解释器,你可以这样做

import code
code.interact(local=dict(globals(), **locals()))

This will allow access to both locals and globals.

这将允许访问本地和全局。

If you want to drop into an IPython interpreter, the IPShellEmbed solution is outdated. Currently what works is:

如果要放入IPython解释器,IPShellEmbed解决方案已过时。目前有效的是:

from IPython import embed
embed()

#1


47  

Inserting

插入

import pdb; pdb.set_trace()

will enter the python debugger at that point

此时将进入python调试器

See here: http://docs.python.org/library/pdb.html

见这里:http://docs.python.org/library/pdb.html

#2


123  

If you want a standard interactive prompt (instead of the debugger, as shown by prestomation), you can do this:

如果你想要一个标准的交互式提示(而不是调试器,如prestomation所示),你可以这样做:

import code
code.interact(local=locals())

See: the code module.

请参阅:代码模块。

If you have IPython installed, and want an IPython shell instead, you can do this for IPython >= 0.11:

如果你安装了IPython,并且想要一个IPython shell,你可以为IPython> = 0.11执行此操作:

import IPython; IPython.embed()

or for older versions:

或旧版本:

from IPython.Shell import IPShellEmbed
ipshell = IPShellEmbed()
ipshell(local_ns=locals())

#3


18  

If you want a default Python interpreter, you can do

如果你想要一个默认的Python解释器,你可以这样做

import code
code.interact(local=dict(globals(), **locals()))

This will allow access to both locals and globals.

这将允许访问本地和全局。

If you want to drop into an IPython interpreter, the IPShellEmbed solution is outdated. Currently what works is:

如果要放入IPython解释器,IPShellEmbed解决方案已过时。目前有效的是:

from IPython import embed
embed()