So I'm trying to populate a table with data from a script. I've tried lots changing lots of parameters etc but can't seem to get it to work. Here's what I've got so far:
所以我试图用脚本中的数据填充表格。我已经尝试过很多改变很多参数等但似乎无法让它工作。这是我到目前为止所得到的:
$(document).ready(function () {
$.get(file + '?op=retrieve&page=1', function (data) {
$.each(data, function (i, elem) {
$('#mainTable').append(
'<tr><td>' + elem.name + '</td><td>' + elem.address '</td></tr>'
)
})
})
I'm currently getting the error: TypeError: e is not an Object. (evaluating 't-1 in e')
我目前收到错误:TypeError:e不是Object。 (评估't'中的't')
Heres a example of the json data:
下面是json数据的一个例子:
{"id":"348141","name":"Birdies","address":"Bridge Street, Tunbridge Wells, TN1 1AH"}]
1 个解决方案
#1
0
From your data, I understood that you are getting an array of js objects.
从您的数据中,我了解到您正在获取一组js对象。
If you see your js code, you are using the following snippet
如果您看到了js代码,则表示您正在使用以下代码段
$.each(data, function (i, elem) { });
$ .each(data,function(i,elem){});
So from the above code, "i" is the index and elem is the current iterating value.
所以从上面的代码中,“i”是索引,elem是当前的迭代值。
So elem.name[i] would be invalid. This is because elem itself is an object which has name property and name is just of type string. So you cannot have name[i].
因此elem.name [i]将无效。这是因为elem本身是一个具有name属性的对象,name只是string类型。所以你不能有名字[i]。
$(document).ready(function () {
$.get(file + '?op=retrieve&page=1', function (data) {
$.each(data, function (i, elem) {
$('#mainTable').append(
'<tr><td>' + elem.name + '</td><td>' + elem.address '</td></tr>'
)
})
})
I assume that "mainTable" element looks something like this
我假设“mainTable”元素看起来像这样
<table>
<tbody id="mainTable">
</tbody>
</table>
#1
0
From your data, I understood that you are getting an array of js objects.
从您的数据中,我了解到您正在获取一组js对象。
If you see your js code, you are using the following snippet
如果您看到了js代码,则表示您正在使用以下代码段
$.each(data, function (i, elem) { });
$ .each(data,function(i,elem){});
So from the above code, "i" is the index and elem is the current iterating value.
所以从上面的代码中,“i”是索引,elem是当前的迭代值。
So elem.name[i] would be invalid. This is because elem itself is an object which has name property and name is just of type string. So you cannot have name[i].
因此elem.name [i]将无效。这是因为elem本身是一个具有name属性的对象,name只是string类型。所以你不能有名字[i]。
$(document).ready(function () {
$.get(file + '?op=retrieve&page=1', function (data) {
$.each(data, function (i, elem) {
$('#mainTable').append(
'<tr><td>' + elem.name + '</td><td>' + elem.address '</td></tr>'
)
})
})
I assume that "mainTable" element looks something like this
我假设“mainTable”元素看起来像这样
<table>
<tbody id="mainTable">
</tbody>
</table>