This is my html form:
这是我的html表单:
<form role="form" id="booking" class="form-horizontal" action="booking.json" method="POST">
<div class="form-group">
<label for="destination">Destination:</label>
<select id="destination" name="destination" class="form-control" title="Select your Destination...">
<option value="Dominican Republic">dominican</option>
<option value="Miami, Florida">miami</option>
<option value="Las Vegas, Nevada">vegas</option>
</select>
</div>
<div class="form-group">
<label for="quantity">Nights:</label>
<input type="number" id="quantity" name="quantity" value="1">
</div>
<div class="form-group">
<button type="submit" class="btn btn-default text-uppercase">Book Trip</button>
</div>
<div class="form-submitted" style="display: none">
</div>
</form>
This is my Ajax:
这是我的Ajax:
$.ajax( form.attr('action'), {
timeout: 3000,
type: 'POST',
contentType: 'application/json',
dataType: 'json',
data: form.serialize(),
beforeSend: function () {
$('.booking-flight').addClass("spinner");
},
complete: function () {
$('.booking-flight').removeClass("spinner");
},
error: function (request, errorType, errorMessage) {
alert(errorMessage);
},
success: function (response) {
console.log($('form').serialize());
form.remove();
var msg = $("<p></p>");
msg.append("Destination: " + response.destination);
msg.append("Nights: " + response.quantity);
$('.booking-flight').hide().html(msg).fadeIn();
}
});
This is my JSON File with random information that I set:
这是我的JSON文件,其中包含我设置的随机信息:
{
"destination": "Dominican Republic",
"totalPrice": 199.99,
"quantity": 5,
"confirmation": 234235
};
How can I retrieve the serialized data that I send from my Ajax and set it to my JSON's File... So that I got the correct data from my form?
如何检索我从Ajax发送的序列化数据并将其设置为我的JSON文件...这样我从表单中获取了正确的数据?
2 个解决方案
#1
You can use the jQuery function .serializeArray();
and then manipulate the response as described here: https://*.com/a/1186309/507384
你可以使用jQuery函数.serializeArray();然后按照此处所述操作响应:https://*.com/a/1186309/507384
#2
You can use json_decode($user_json_data)
你可以使用json_decode($ user_json_data)
json_decode($user_json_data)
would return a object
andjson_decode($user_json_data,TRUE)
would return a array
json_decode($ user_json_data)将返回一个对象,json_decode($ user_json_data,TRUE)将返回一个数组
#1
You can use the jQuery function .serializeArray();
and then manipulate the response as described here: https://*.com/a/1186309/507384
你可以使用jQuery函数.serializeArray();然后按照此处所述操作响应:https://*.com/a/1186309/507384
#2
You can use json_decode($user_json_data)
你可以使用json_decode($ user_json_data)
json_decode($user_json_data)
would return a object
andjson_decode($user_json_data,TRUE)
would return a array
json_decode($ user_json_data)将返回一个对象,json_decode($ user_json_data,TRUE)将返回一个数组