非IMU模式下DML语句产生的REDO日志内容格式解读

时间:2023-12-28 17:03:26

实验内容:非IMU模式下DML语句产生的REDO日志内容格式解读

最详细的解读是UPDATE的。

实验环境准备

11G中默认是开启IMU特性的,做此实验需要关闭此特性。

alter system set "_in_memory_undo"=false;

alter system set "_in_memory_undo"=true;  --实验结束后使用此语句改回使用IMU特性。


修改参数完成后,重启数据库:

shutdown immediate;

startup;


准备好实验用的表----BYS.DEPT表。

SYS@ bys3>select object_id from dba_objects where object_name='DEPT';

 OBJECT_ID

----------

     22327

SYS@ bys3>select * from bys.dept;

    DEPTNO DNAME          LOC

---------- -------------- -------------

        10 ACCOUNTING     NEW YORK

        20 RESEARCH       DALLAS

        40 OPERATIONS     BOSTON

        11 chedan         bj

        22 test           sh       

BYS@ bys3>col file_name for a35

SYS@ bys3>col name for a15

SYS@ bys3>
select a.file_id,b.ts#,b.name,a.file_name from dba_data_files a,v$tablespace b where a.TABLESPACE_NAME=b.name;

   FILE_ID        TS# NAME            FILE_NAME

---------- ---------- --------------- -----------------------------------

         1          0 SYSTEM          /u01/oradata/bys3/system01.dbf

         2          1 SYSAUX          /u01/oradata/bys3/sysaux01.dbf

         3          2 UNDOTBS1        /u01/oradata/bys3/undotbs01.dbf

         4          4 USERS           /u01/oradata/bys3/user01.dbf

###################################################


开始实验分三步,分别是插入、更新、删除语句的操作。
最详细的解读是UPDATE的。

实验一:insert 操作的REDO日志解读

会话1: --SYS用户切换日志并查出当前日志名:

SYS@ bys3>alter system switch logfile;

System altered.

col  MEMBER for a30

SYS@ bys3>select a.group#,a.sequence#,a.archived,a.status,b.type,b.member from v$log a,v$logfile b where a.group#=b.group#;

    GROUP#  SEQUENCE# ARC STATUS           TYPE    MEMBER

---------- ---------- --- ---------------- ------- ------------------------------

         1        310 NO  CURRENT          ONLINE  /u01/oradata/bys3/redo01.log

         2        308 YES INACTIVE         ONLINE  /u01/oradata/bys3/redo02.log

         3        309 YES ACTIVE           ONLINE  /u01/oradata/bys3/redo03.log


普通用户做插入语句:

SYS@ bys3>conn bys/bys

select * from dept;

Connected.

BYS@ bys3>

    DEPTNO DNAME          LOC

---------- -------------- -------------

        10 ACCOUNTING     NEW YORK

        20 RESEARCH       DALLAS

        40 OPERATIONS     BOSTON

        11 chedan         bj

        22 test           sh

BYS@ bys3>set time on

20:34:07 BYS@ bys3>insert into dept values(33,'imutest','hz');

1 row created.


20:34:12 BYS@ bys3>commit;
Commit complete.

会话2:DUMP当前REDO日志:

SYS@ bys3>alter system dump logfile '/u01/oradata/bys3/redo01.log';

System altered.

SYS@ bys3>select value from v$diag_info where name like 'De%' ;

VALUE

----------------------------------------------------------------------------------------------------

/u01/diag/rdbms/bys3/bys3/trace/bys3_ora_29063.trc

######################


查看此TRACE文件: 方法是:vi /u01/diag/rdbms/bys3/bys3/trace/bys3_ora_29063.trc 然后搜索修改的对象的OBJECT_ID--     22327


详解参考下一步的UPDATE的REDO讲解。

REDO RECORD - Thread:1
RBA: 0x000136.0000000d.0010 LEN: 0x01a0 VLD: 0x05


SCN: 0x0000.00702f08 SUBSCN:  1 01/06/2014 20:34:13

(LWN RBA: 0x000136.0000000d.0010 LEN: 0002 NST: 0001 SCN: 0x0000.00702f08)


CHANGE #1 TYP:0 CLS:21
AFN:3 DBA:0x00c000a0 OBJ:4294967295 SCN:0x0000.00702eda SEQ:1
OP:5.2 ENC:0 RBL:0

ktudh redo: slt: 0x0003 sqn: 0x00000eaa flg: 0x0012 siz: 112 fbi: 0

            uba: 0x00c01ac7.0250.25    pxid:  0x0000.000.00000000


CHANGE #2 TYP:0 CLS:22
AFN:3 DBA:0x00c01ac7 OBJ:4294967295 SCN:0x0000.00702ed9 SEQ:3
OP:5.1 ENC:0 RBL:0

ktudb redo: siz: 112 spc: 3494 flg: 0x0012 seq: 0x0250 rec: 0x25

            xid:  0x0003.003.00000eaa

ktubl redo: slt: 3 rci: 0 opc: 11.1 [
objn: 22327 objd: 22327 tsn: 4]    -------
tsn: 4

插入的这个是在表空间号为4--
OBJ:22327--是插入的对象的OBJECT_ID

Undo type:  Regular undo        Begin trans    Last buffer split:  No

Temp Object:  No

Tablespace Undo:  No

             0x00000000  prev ctl uba: 0x00c01ac7.0250.22

prev ctl max cmt scn:  0x0000.007029ac  prev tx cmt scn:  0x0000.007029d6

txn start scn:  0xffff.ffffffff  logon user: 32  prev brb: 12589763  prev bcl: 0 BuExt idx: 0 flg2: 0

KDO undo record:

KTB Redo

op: 0x03  ver: 0x01

compat bit: 4 (post-11) padding: 1

op: Z

KDO Op code: DRP row dependencies Disabled

  xtype: XA flags: 0x00000000  bdba: 0x010000ff  hdba: 0x010000fa

itli: 1  ispac: 0  maxfr: 4858

tabn: 0 slot: 0(0x0)


CHANGE #3 TYP:0 CLS:1
AFN:4 DBA:0x010000ff OBJ:22327 SCN:0x0000.003eec75 SEQ:1
OP:11.2 ENC:0 RBL:0   --
OP:11.2 这个应该是插入的操作的了。

KTB Redo               -----
AFN:4
插入的这个是在4号数据文件中--
OBJ:22327--是插入的对象的OBJECT_ID

op: 0x01  ver: 0x01

compat bit: 4 (post-11) padding: 1

op: F  xid:  0x0003.003.00000eaa    uba: 0x00c01ac7.0250.25


KDO Op code: IRP row dependencies Disabled

  xtype: XA flags: 0x00000000  bdba: 0x010000ff  hdba: 0x010000fa

itli: 1  ispac: 0  maxfr: 4858

tabn: 0 slot: 0(0x0) size/delt: 17

fb: --H-FL-- lb: 0x1  cc: 3

null: ---


col  0: [ 2]  c1 22    ---插入语句是:insert into dept values(33,'imutest','hz');  对应是:select dump(33,16) from dual;  --要注意数字在DUMP时不要加单引号
col  1: [ 7]  69 6d 75 74 65 73 74    --对应select dump('imutest',16) from dual;    [7]--中括号里的是字节数,col  1:对应的是第二列,
col  2: [ 2]  68 7a    ---对应 select dump('hz',16) from dual;    --中括号里的是字节数  col  2: 对应 的是第三列

REDO RECORD - Thread:1 RBA: 0x000136.0000000d.01b0 LEN: 0x0060 VLD: 0x01

SCN: 0x0000.00702f09 SUBSCN:  1 01/06/2014 20:34:13                                                    ----
OP:5.4,提交操作

CHANGE #1 TYP:0 CLS:21
AFN:3 DBA:0x00c000a0 OBJ:4294967295 SCN:0x0000.00702f08 SEQ:1
OP:5.4 ENC:0 RBL:0

ktucm redo:
slt: 0x0003 sqn: 0x00000eaa srt: 0 sta: 9 flg: 0x2 ktucf redo:
uba: 0x00c01ac7.0250.25ext: 12 spc: 3380 fbi: 0

############################

实验二:update 操作的REDO日志解读

会话3: --SYS用户切换日志:

SYS@ bys3>alter system switch logfile;

System altered.

SYS@ bys3>col  MEMBER for a30

SYS@ bys3>select a.group#,a.sequence#,a.archived,a.status,b.type,b.member from v$log a,v$logfile b where a.group#=b.group#;

    GROUP#  SEQUENCE# ARC STATUS           TYPE    MEMBER

---------- ---------- --- ---------------- ------- ------------------------------

         1        310 YES ACTIVE           ONLINE  /u01/oradata/bys3/redo01.log

         2        311 NO  CURRENT          ONLINE  /u01/oradata/bys3/redo02.log

         3        309 YES INACTIVE         ONLINE  /u01/oradata/bys3/redo03.log


切换到普通用户做更新语句:

SYS@ bys3>conn bys/bys

Connected.

BYS@ bys3>select * from dept;

    DEPTNO DNAME          LOC

---------- -------------- -------------

        10 ACCOUNTING     NEW YORK

        20 RESEARCH       DALLAS

        40 OPERATIONS     BOSTON

        11 chedan         bj

        22 test           sh

        33 imutest        hz

6 rows selected.

BYS@ bys3>set time on

20:39:23 BYS@ bys3>update dept set dname='database' where deptno=11;

1 row updated.


20:39:43 BYS@ bys3>commit;
Commit complete.
20:39:46 BYS@ bys3>

会话4:DUMP当前REDO日志:

SYS@ bys3>alter system dump logfile '/u01/oradata/bys3/redo02.log';

System altered.

SYS@ bys3>select value from v$diag_info where name like 'De%' ;

VALUE

----------------------------------------------------------------------------------------------------

/u01/diag/rdbms/bys3/bys3/trace/bys3_ora_29141.trc

##############


查看此TRACE文件: 方法是:vi /u01/diag/rdbms/bys3/bys3/trace/bys3_ora_29141.trc 然后搜索修改的对象的OBJECT_ID:22327       

       

UPDATE 一行记录产生一个REDO RECORD,提交产生一个REDO RECORD。非IMU下如果一个UPDATE更新多行,则会产生多条REDO RECORD。关于这个UPDATE语句 产生多少REDO RECORD的话题详见另一篇:
非IMU模式下一条update语句产生REDO RECORD条数的探究

######
一个REDO RECORD: RECORD头+CHANGE VECTOR组成(一个CV就是一个操作)


REDO RECORD - Thread:1 RBA: 0x000137.00000003.0010 LEN: 0x01ec VLD: 0x05

SCN: 0x0000.00702fe0 SUBSCN:  1 01/06/2014 20:39:45

(LWN RBA: 0x000137.00000003.0010 LEN: 0001 NST: 0001 SCN: 0x0000.00702fdf)


##以上是日志头,Thread:1 线程号,RAC时会有1,2等

RBA: 0x000137.00000003.0010 将16进制转换为十进制分别是日志文件号、日志块号、在块上第N字节

VLD: 0x05日志类型;

SCN: 0x0000.00702fe0 SUBSCN:  1 01/06/2014 20:39:45    


--是此REDO条目产生时的SCN号,转为十进制现转为时间戳为:06-JAN-14 08.39.42,  更新语句完成是在20:39:43 BYS@bys3>commit;

(LWN RBA: 0x000137.00000003.0010 LEN: 0001 NST: 0001 SCN: 0x0000.00702fdf)

括号中SCN: SCN: 0x0000.00702fdf  比上一句:SCN: 0x0000.00702fe0 SUBSCN:  1 01/06/2014 20:39:45
   少了1个SCN。

######


CHANGE #1 TYP:0 CLS:17 AFN:3 DBA:0x00c00080 OBJ:4294967295 SCN:0x0000.00702f9a SEQ:1 OP:5.2 ENC:0 RBL:0

ktudh redo: slt: 0x000f sqn: 0x00000e9c flg: 0x0012 siz: 164 fbi: 0

            uba: 0x00c01cbf.0250.0f    pxid:  0x0000.000.00000000

### #####################
事务信息


TYP:0 普通块 ,CLS:17 class大于16是UNDO块-递增。AFN:3 绝对文件号dba_data_files.file_id--这里是UNDO文件的文件号
DBA:0x00c00080 数据块在内存中地址
OBJ:4294967295 --十进制,转为16进制是FFFFFFFF
SCN:0x0000.00702f9a  转换为16进制可与操作时对比
OP:5.2 -> operation code 向UNDO段头的事务表写事务信息-事务开始
uba: 0x00c01cbf.0250.0f  UNDO块地址

####################


CHANGE #2 TYP:0
CLS:18 AFN:3 DBA:0x00c01cbf OBJ:4294967295 SCN:0x0000.00702f99 SEQ:2 OP:5.1 ENC:0 RBL:0

##
OP:5.1 --把数据修改前值放到UNDO   --AFN:3 --在UNDO文件里操作,UNDO文件号是3。。
CLS:18 --比
CHANGE #1中大1,顺序增长哈哈

ktudb redo: siz: 164 spc: 6494 flg: 0x0012 seq: 0x0250 rec: 0x0f

            xid:  0x0001.00f.00000e9c

ktubl redo: slt: 15 rci: 0 opc: 11.1
[objn: 22327 objd: 22327 tsn: 4]    -------
tsn: 4,
插入的这个是在表空间号-USERS的表空间号,--
OBJ:22327--是插入的对象的OBJECT_ID

Undo type:  Regular undo        Begin trans    Last buffer split:  No

Temp Object:  No

Tablespace Undo:  No

             0x00000000  prev ctl uba: 0x00c01cbf.0250.0d

prev ctl max cmt scn:  0x0000.00702afa  prev tx cmt scn:  0x0000.00702b2e

txn start scn:  0xffff.ffffffff  logon user: 32  prev brb: 12590267  prev bcl: 0 BuExt idx: 0 flg2: 0


KDO undo record:

KTB Redo

op: 0x04  ver: 0x01

compat bit: 4 (post-11) padding: 1

op: L  itl: xid:  0x0005.008.00000e9d uba: 0x00c01840.02e4.13

                      flg: C---    lkc:  0     scn: 0x0000.00702b1f

KDO Op code: URP row dependencies Disabled

  xtype: XA flags: 0x00000000  bdba: 0x010000fd  hdba: 0x010000fa

itli: 1  ispac: 0  maxfr: 4858

tabn: 0 slot: 5(0x5) flag: 0x2c lock: 0 ckix: 0

ncol: 3 nnew: 1
size: -2  
##列字符长度减少2:
chedan减去database就是-2---根据多次update并DUMP的日志来看,这里的
size的值应该是:当前
CHANGE中的值减去另一个


col  1: [ 6]  63 68 65 64 61 6e   --修改语句是:update dept set dname='database' where deptno=11; deptno=11时的为chedan-DUMP为16进制,与col  1: [ 6]  63 68 65 64 61 6e对应,[ 6]


chedan对应,
col  1是第二列--修改的dname列就是第二列。

SYS@ bys3>
select dump('chedan',16) from dual;

DUMP('CHEDAN',16)

-------------------------------


Typ=96 Len=6: 63,68,65,64,61,6e

##############


CHANGE #3 TYP:2 CLS:1
AFN:4DBA:0x010000fd
OBJ:22327
SCN:0x0000.00702d7aSEQ:1 OP:11.5 ENC:0 RBL:0


## OP:11.19 或者OP:11.5都是--UPDATE语句,开始修改数据,  AFN:4 --这次是在USERS表空间修改数据-文件号就是4

KTB Redo

op: 0x11  ver: 0x01

compat bit: 4 (post-11) padding: 1

op: F  xid:  0x0001.00f.00000e9c    uba: 0x00c01cbf.0250.0f

Block cleanout record, scn:  0x0000.00702fe0 ver: 0x01 opt: 0x02, entries follow...

  itli: 1  flg: 2  scn: 0x0000.00702b1f

  itli: 2  flg: 2  scn: 0x0000.00702d7a

KDO Op code: URP row dependencies Disabled


###此语句也说明是UPDATE语句,URP row dependencies Disabled --URP=UPDATE ROW PIECE。有时会是:KDO Op code:21 row dependencies Disabled

  xtype: XA flags: 0x00000000  bdba: 0x010000fd  hdba: 0x010000fa

itli: 1  ispac: 0  maxfr: 4858

tabn: 0 slot: 5(0x5) flag: 0x2c lock: 1 ckix: 0


ncol: 3 nnew: 1 size: 2   ##size: 2,列字符长度增加2:database减去
chedan---根据多次update并DUMP的日志来看,这里的
size的值应该是:当前
CHANGE中的值减去另一个


col  1: [ 8]  64 61 74 61 62 61 73 65   ---update dept set dname='database' where deptno=11;,对应
select dump('database',16) from dual;   
col  1: [ 8]  ---第二列,8位,

####################################################

REDO RECORD - Thread:1 RBA: 0x000137.00000004.0010 LEN: 0x008c VLD: 0x05

SCN: 0x0000.00702fe2 SUBSCN:  1 01/06/2014 20:39:46

(LWN RBA: 0x000137.00000004.0010 LEN: 0001 NST: 0001 SCN: 0x0000.00702fe1)

CHANGE #1 TYP:0 CLS:17
AFN:3 DBA:0x00c00080 OBJ:4294967295 SCN:0x0000.00702fe0 SEQ:1
OP:5.4 ENC:0 RBL:0

ktucm redo:
slt: 0x000f sqn: 0x00000e9c srt: 0 sta: 9 flg: 0x2 ktucf redo: uba: 0x00c01cbf.0250.0f ext: 4 spc: 6328 fbi: 0

###########


OP:5.4 表明是提交操作。
CHANGE #1 TYP:0 CLS:17 AFN:3 DBA:0x00c00080 OBJ:4294967295 SCN:0x0000.00702fe0 SEQ:1 OP:5.4 ENC:0 RBL:0
AFN:3 对应的是UNDO文件,
slt: 0x000f  修改了UNDO文件的这个事务槽

SCN: 0x0000.00702fe2 SUBSCN:  1 01/06/2014 20:39:46  提交操作的时间 :

20:39:43 BYS@ bys3>commit;

Commit complete.

20:39:46 BYS@ bys3>

########################################

实验三:delete 操作的REDO日志解读

会话5: --SYS用户切换日志:

alter system switch logfile;

SYS@ bys3>col member for a30

SYS@ bys3>select a.group#,a.sequence#,a.archived,a.status,b.type,b.member from v$log a,v$logfile b where a.group#=b.group#;

    GROUP#  SEQUENCE# ARC STATUS           TYPE    MEMBER

---------- ---------- --- ---------------- ------- ------------------------------

         1        310 YES INACTIVE         ONLINE  /u01/oradata/bys3/redo01.log

         2        311 YES ACTIVE           ONLINE  /u01/oradata/bys3/redo02.log

         3        312 NO  CURRENT          ONLINE  /u01/oradata/bys3/redo03.log


切换到普通用户做删除语句:

conn bys/bys

BYS@ bys3>select * from dept;

    DEPTNO DNAME          LOC

---------- -------------- -------------

        10 ACCOUNTING     NEW YORK

        20 RESEARCH       DALLAS

        40 OPERATIONS     BOSTON

        11 database       bj

        22 test           sh

        33 imutest        hz

6 rows selected.

BYS@ bys3>set time on

20:43:18 BYS@ bys3>delete dept where deptno=33;

1 row deleted.

20:43:25 BYS@ bys3>commit;

Commit complete.


会话6,DUMP当前REDO日志:

SYS@ bys3>alter system dump logfile '/u01/oradata/bys3/redo03.log';

System altered.

SYS@ bys3>select value from v$diag_info where name like 'De%' ;

VALUE

----------------------------------------------------------------------------------------------------

/u01/diag/rdbms/bys3/bys3/trace/bys3_ora_29214.trc

##############


查看此TRACE文件: 方法是:vi /u01/diag/rdbms/bys3/bys3/trace/bys3_ora_29214.trc 然后搜索修改的对象的OBJECT_ID:22327

REDO RECORD - Thread:1 RBA: 0x000138.0000002b.0010 LEN: 0x01c8 VLD: 0x05

SCN: 0x0000.0070306c SUBSCN:  1 01/06/2014 20:43:26

(LWN RBA: 0x000138.0000002b.0010 LEN: 0002 NST: 0001 SCN: 0x0000.0070306b)

CHANGE #1 TYP:0 CLS:29 AFN:3 DBA:0x00c000e0 OBJ:4294967295 SCN:0x0000.0070303f SEQ:1 OP:5.2 ENC:0 RBL:0

ktudh redo: slt: 0x0008 sqn: 0x00000e9b flg: 0x0012 siz: 168 fbi: 0

            uba: 0x00c0193e.02b8.03    pxid:  0x0000.000.00000000


CHANGE #2 TYP:0 CLS:30 AFN:3 DBA:0x00c0193e OBJ:4294967295 SCN:0x0000.0070303e SEQ:1 OP:5.1 ENC:0 RBL:0

ktudb redo: siz: 168 spc: 7794 flg: 0x0012 seq: 0x02b8 rec: 0x03

            xid:  0x0007.008.00000e9b

ktubl redo: slt: 8 rci: 0 opc: 11.1 [objn: 22327 objd: 22327 tsn: 4]

Undo type:  Regular undo        Begin trans    Last buffer split:  No

Temp Object:  No

Tablespace Undo:  No

             0x00000000  prev ctl uba: 0x00c0193e.02b8.02

prev ctl max cmt scn:  0x0000.00702b2d  prev tx cmt scn:  0x0000.00702b3e

txn start scn:  0xffff.ffffffff  logon user: 32  prev brb: 12589367  prev bcl: 0 BuExt idx: 0 flg2: 0

KDO undo record:

KTB Redo

op: 0x03  ver: 0x01

compat bit: 4 (post-11) padding: 1

op: Z

KDO Op code: IRP row dependencies Disabled

  xtype: XA flags: 0x00000000  bdba: 0x010000ff  hdba: 0x010000fa

itli: 2  ispac: 0  maxfr: 4858

tabn: 0 slot: 0(0x0) size/delt: 17

fb: --H-FL-- lb: 0x0  cc: 3

null: ---


col  0: [ 2]  c1 22    ---记录删除前的原值,delete dept where deptno=33;   删除的是这一行值: 33 imutest        hz
col  1: [ 7]  69 6d 75 74 65 73 74

col  2: [ 2]  68 7a
###################
BYS@ bys3>select dump(33,16),dump('imutest',16),dump('hz',16) from dual;
DUMP(33,16)        DUMP('IMUTEST',16)                 DUMP('HZ',16)
------------------ ---------------------------------- -------------------
Typ=2 Len=2: c1,22 Typ=96 Len=7: 69,6d,75,74,65,73,74 Typ=96 Len=2: 68,7a
#####################

CHANGE #3 TYP:2 CLS:1 AFN:4 DBA:0x010000ff OBJ:22327 SCN:0x0000.00702f09 SEQ:1 OP:11.3 ENC:0 RBL:0

KTB Redo

op: 0x11  ver: 0x01

compat bit: 4 (post-11) padding: 1

op: F  xid:  0x0007.008.00000e9b    uba: 0x00c0193e.02b8.03

Block cleanout record, scn:  0x0000.0070306c ver: 0x01 opt: 0x02, entries follow...

  itli: 1  flg: 2  scn: 0x0000.00702f09

KDO Op code: DRP row dependencies Disabled

  xtype: XA flags: 0x00000000  bdba: 0x010000ff  hdba: 0x010000fa

itli: 2  ispac: 0  maxfr: 4858

tabn: 0 slot: 0(0x0)

REDO RECORD - Thread:1 RBA: 0x000138.0000002b.01d8 LEN: 0x0060 VLD: 0x01

SCN: 0x0000.0070306d SUBSCN:  1 01/06/2014 20:43:26

CHANGE #1 TYP:0 CLS:29 AFN:3 DBA:0x00c000e0 OBJ:4294967295 SCN:0x0000.0070306c SEQ:1 OP:5.4 ENC:0 RBL:0

ktucm redo: slt: 0x0008 sqn: 0x00000e9b srt: 0 sta: 9 flg: 0x2 ktucf redo: uba: 0x00c0193e.02b8.03 ext: 3 spc: 7624 fbi: 0