（PHP，谷歌图表）饼图使用PHP页面中的数据

I'm new to PHP, I tried to create the pie chart on my PHP page but it shows nothing.

我是PHP的新手,我试图在我的PHP页面上创建饼图,但它没有显示任何内容。

These are my codes (I put all codes in HTML section)

这些是我的代码(我把所有代码放在HTML部分)

and this the piechart.php parts

这就是piechart.php的部分

<script type="text/javascript">
  google.charts.load('current', {'packages':['corechart']});
  google.charts.setOnLoadCallback(drawChart);
  function drawChart() {

    var data = google.visualization.arrayToDataTable([
      ['Position', 'Applicant(s)'],

      <?php 
        for($i = 0; $i < $table_counter; $i++){
      ?> 

      [<?=$pos_chart[$i]?>, <?=$tapp_chart[$i]?>],

      <?php 
        }
      ?>

    ]);

    var options = {
      title: 'Pie chart of Total Applicants'
    };

    var chart = new google.visualization.PieChart(document.getElementById('piechart'));

    chart.draw(data, options);
  }
</script>

<div id="piechart" style="width: 900px; height: 500px;"></div>

The result for pie chart turns out only the big whole white space like this.

饼图的结果只显示出像这样的大整个空白区域。

I don't know why. Please help.

我不知道为什么。请帮忙。

1 个解决方案

#1

the array values aren't being printed to JavaScript

数组值未打印到JavaScript

need to use something like

需要使用类似的东西

<?=$pos_chart[$i]?>

<?php echo $tapp_chart[$i]?>

and don't see the need for the if statement

并且不认为需要if语句

try this...

var data = google.visualization.arrayToDataTable([
  ['Position', 'Applicant(s)'],

  <?php
    for($i = 0; $i < $table_counter; $i++){
  ?>

  [<?="'".$pos_chart[$i]."'"?>,   <?=$tapp_chart[$i]?>],

  <?php
    }
  ?>

]);

#1