本文实例讲述了php正则判断是否为合法身份证号的方法。分享给大家供大家参考，具体如下：
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/**
* 判断是否为合法的身份证号码
* @param $mobile
* @return int
*/
function isCreditNo($vStr){
$vCity = array(
'11','12','13','14','15','21','22',
'23','31','32','33','34','35','36',
'37','41','42','43','44','45','46',
'50','51','52','53','54','61','62',
'63','64','65','71','81','82','91'
);
if (!preg_match('/^([\d]{17}[xX\d]|[\d]{15})$/', $vStr)) return false;
if (!in_array(substr($vStr, 0, 2), $vCity)) return false;
$vStr = preg_replace('/[xX]$/i', 'a', $vStr);
$vLength = strlen($vStr);
if ($vLength == 18) {
$vBirthday = substr($vStr, 6, 4) . '-' . substr($vStr, 10, 2) . '-' . substr($vStr, 12, 2);
} else {
$vBirthday = '19' . substr($vStr, 6, 2) . '-' . substr($vStr, 8, 2) . '-' . substr($vStr, 10, 2);
}
if (date('Y-m-d', strtotime($vBirthday)) != $vBirthday) return false;
if ($vLength == 18) {
$vSum = 0;
for ($i = 17 ; $i >= 0 ; $i--) {
$vSubStr = substr($vStr, 17 - $i, 1);
$vSum += (pow(2, $i) % 11) * (($vSubStr == 'a') ? 10 : intval($vSubStr , 11));
}
if($vSum % 11 != 1) return false;
}
return true;
}
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希望本文所述对大家PHP程序设计有所帮助。