function convertImgToBase64(url){
var canvas = document.createElement('CANVAS');
var ctx = canvas.getContext('2d');
var img = new Image;
img.crossOrigin = 'Anonymous';
img.onload = function(){
canvas.height = img.height;
canvas.width = img.width;
ctx.drawImage(img,0,0);
var dataURL = canvas.toDataURL('image/png',"");
alert(dataURL);
canvas = null;
};
img.src = url;
}
var url_to_be_converted = "http://www.google.com/image/sample"
convertImgToBase64(url_to_be_converted);
Alert(dataURL) does not showing any result.No pop up is generated there? How to solve this?
What wrong there?
警报(dataURL)没有显示任何结果。那里没有生成弹出窗口?怎么解决这个?那有什么不对?
1 个解决方案
#1
1
There is a cross origin problem ... try using this function
有一个交叉原点问题...尝试使用此功能
function convertImgToBase64(url)
{
var canvas = document.createElement('CANVAS');
img = document.createElement('img'),
img.src = url;
img.onload = function()
{
canvas.height = img.height;
canvas.width = img.width;
var dataURL = canvas.toDataURL('image/png');
alert(dataURL);
canvas = null;
};
}
I removed the context and I loaded the image in a different way
我删除了上下文,我以不同的方式加载了图像
#1
1
There is a cross origin problem ... try using this function
有一个交叉原点问题...尝试使用此功能
function convertImgToBase64(url)
{
var canvas = document.createElement('CANVAS');
img = document.createElement('img'),
img.src = url;
img.onload = function()
{
canvas.height = img.height;
canvas.width = img.width;
var dataURL = canvas.toDataURL('image/png');
alert(dataURL);
canvas = null;
};
}
I removed the context and I loaded the image in a different way
我删除了上下文,我以不同的方式加载了图像