Here is my question:
这是我的问题:
k = "_opqrst_ _ _ _ yzabc_ _ _ _hijklm"
dict_ = dict.fromkeys(zip(string.ascii_lowercase , k))
the result is:
结果是:
{'d': 'q', 'e': 'r', 'x': 'k', 'i': '_', 'o': 'b', 'b': 'o', 'm': 'z', 'k': '_',
'j': '_', 'u': 'h', 'n': 'a', 's': '_', 'a': '_', 'w': 'j', 'v': 'i', 'c': 'p',
't': '_', 'z': 'm', 'f': 's', 'l': 'y', 'p': 'c', 'g': 't', 'h': '_', 'y': 'l',
'r': '_', 'q': '_'}
I want my programme showing like this
我希望我的程序显示如下
{'D,d': 'q', 'E,e': 'r', 'X,x': 'k', 'I,i': '_', 'O,o': 'b', 'B,b': 'o', ......}
That means {'capital, small alphabet': ' '}
这意味着{'资本,小字母':''}
2 个解决方案
#1
0
{'D,d': 'q'}
is still mapping a single key to a value. To map multiple keys to the same value would be something like
{'D,d':'q'}仍然将单个键映射到值。将多个键映射到相同的值将是类似的
from itertools import cycle
from string import ascii_letters
k = '_opqrst____yzabc____hijklm'
d = dict(zip(ascii_letters, cycle(k)))
d
is then
那么就是
{'V': 'i', 'j': '_', 'E': 'r', 'B': 'o', 'S': '_', 'e': 'r', 'G': 't',
'l': 'y', 'O': 'b', 'k': '_', 'Y': 'l', 'o': 'b', 'R': '_', 't': '_', 'g':
't', 'v': 'i', 'A': '_', 'C': 'p', 'u': 'h', 'J': '_', 'N': 'a', 'I': '_',
'w': 'j', 'b': 'o', 'z': 'm', 'x': 'k', 'q': '_', 'a': '_', 'm': 'z', 'X':
'k', 'i': '_', 'h': '_', 'p': 'c', 'W': 'j', 'r': '_', 'd': 'q', 'U': 'h',
'P': 'c', 'F': 's', 'c': 'p', 'f': 's', 'y': 'l', 'D': 'q', 'Z': 'm', 's':
'_', 'n': 'a', 'H': '_', 'Q': '_', 'M': 'z', 'L': 'y', 'T': '_', 'K': '_'}
If you want the 'D,d'
keys, you can do
如果你想要'D,d'键,你可以做到
from string import ascii_lowercase
d = {'{},{}'.format(a.upper(), a): b for a, b in zip(ascii_lowercase, k)}
#2
0
You will need to construct your keys, then build the dictionary:
您需要构建密钥,然后构建字典:
import string
k = "_opqrst_ _ _ _ yzabc_ _ _ _hijklm"
k_wthout_whites = ''.join([c for c in k if c != ' ']) # removing white space
keys = [','.join(elt) for elt in (zip(string.ascii_uppercase, string.ascii_lowercase))]
dict_ = {key: val for key, val in zip(keys, k_wthout_whites)}
dict_
output:
{'A,a': '_',
'B,b': 'o',
'C,c': 'p',
'D,d': 'q',
'E,e': 'r',
'F,f': 's',
'G,g': 't',
'H,h': '_',
'I,i': '_',
'J,j': '_',
'K,k': '_',
'L,l': 'y',
'M,m': 'z',
'N,n': 'a',
'O,o': 'b',
'P,p': 'c',
'Q,q': '_',
'R,r': '_',
'S,s': '_',
'T,t': '_',
'U,u': 'h',
'V,v': 'i',
'W,w': 'j',
'X,x': 'k',
'Y,y': 'l',
'Z,z': 'm'}
#1
0
{'D,d': 'q'}
is still mapping a single key to a value. To map multiple keys to the same value would be something like
{'D,d':'q'}仍然将单个键映射到值。将多个键映射到相同的值将是类似的
from itertools import cycle
from string import ascii_letters
k = '_opqrst____yzabc____hijklm'
d = dict(zip(ascii_letters, cycle(k)))
d
is then
那么就是
{'V': 'i', 'j': '_', 'E': 'r', 'B': 'o', 'S': '_', 'e': 'r', 'G': 't',
'l': 'y', 'O': 'b', 'k': '_', 'Y': 'l', 'o': 'b', 'R': '_', 't': '_', 'g':
't', 'v': 'i', 'A': '_', 'C': 'p', 'u': 'h', 'J': '_', 'N': 'a', 'I': '_',
'w': 'j', 'b': 'o', 'z': 'm', 'x': 'k', 'q': '_', 'a': '_', 'm': 'z', 'X':
'k', 'i': '_', 'h': '_', 'p': 'c', 'W': 'j', 'r': '_', 'd': 'q', 'U': 'h',
'P': 'c', 'F': 's', 'c': 'p', 'f': 's', 'y': 'l', 'D': 'q', 'Z': 'm', 's':
'_', 'n': 'a', 'H': '_', 'Q': '_', 'M': 'z', 'L': 'y', 'T': '_', 'K': '_'}
If you want the 'D,d'
keys, you can do
如果你想要'D,d'键,你可以做到
from string import ascii_lowercase
d = {'{},{}'.format(a.upper(), a): b for a, b in zip(ascii_lowercase, k)}
#2
0
You will need to construct your keys, then build the dictionary:
您需要构建密钥,然后构建字典:
import string
k = "_opqrst_ _ _ _ yzabc_ _ _ _hijklm"
k_wthout_whites = ''.join([c for c in k if c != ' ']) # removing white space
keys = [','.join(elt) for elt in (zip(string.ascii_uppercase, string.ascii_lowercase))]
dict_ = {key: val for key, val in zip(keys, k_wthout_whites)}
dict_
output:
{'A,a': '_',
'B,b': 'o',
'C,c': 'p',
'D,d': 'q',
'E,e': 'r',
'F,f': 's',
'G,g': 't',
'H,h': '_',
'I,i': '_',
'J,j': '_',
'K,k': '_',
'L,l': 'y',
'M,m': 'z',
'N,n': 'a',
'O,o': 'b',
'P,p': 'c',
'Q,q': '_',
'R,r': '_',
'S,s': '_',
'T,t': '_',
'U,u': 'h',
'V,v': 'i',
'W,w': 'j',
'X,x': 'k',
'Y,y': 'l',
'Z,z': 'm'}