Different 'ng-model name' in ng repeat - Possible?
ng重复中的'ng-model name'不同 - 可能吗?
<div ng-repeat="todo in todos">
<input type="text" ng-model="tag">
<button type="submit"ng-click="addTodo(todo._id)">Add</button>
</div>
In this case, there are some repeat todo item (based on todos json data) will show on frontend
在这种情况下,有一些重复todo项目(基于todos json数据)将在前端显示
My Problem: What i type on any input field , all input field showing same data
我的问题:我在任何输入字段上键入的内容,所有输入字段显示相同的数据
I need different ng-model name on each input field , I guess like this ng-model="tag($index)"
我需要在每个输入字段上使用不同的ng-model名称,我想这样的ng-model =“tag($ index)”
3 个解决方案
#1
2
You could place the newly created model inside tag array by its $index
, while declaring model inside the tag
you should use array notation []
instead of ()
您可以通过其$ index将新创建的模型放在标记数组中,同时在标记内声明模型,您应该使用数组表示法[]而不是()
ng-model="tag($index)"
should be
应该
ng-model="tag[$index]"
Markup
标记
<div ng-repeat="todo in todos">
<input type="text" ng-model="tag[$index]">
<button type="submit"ng-click="addTodo(todo._id)">Add</button>
</div>
#2
2
It is possible like below
有可能如下
<div ng-repeat="todo in todos">
<input type="text" ng-model="tag[todo]"> <--todo.key-->
<button type="submit"ng-click="addTodo(todo._id)">Add</button>
</div>
#3
1
You can do it like this:
你可以这样做:
<input type="text" ng-model="todo.tag">
#1
2
You could place the newly created model inside tag array by its $index
, while declaring model inside the tag
you should use array notation []
instead of ()
您可以通过其$ index将新创建的模型放在标记数组中,同时在标记内声明模型,您应该使用数组表示法[]而不是()
ng-model="tag($index)"
should be
应该
ng-model="tag[$index]"
Markup
标记
<div ng-repeat="todo in todos">
<input type="text" ng-model="tag[$index]">
<button type="submit"ng-click="addTodo(todo._id)">Add</button>
</div>
#2
2
It is possible like below
有可能如下
<div ng-repeat="todo in todos">
<input type="text" ng-model="tag[todo]"> <--todo.key-->
<button type="submit"ng-click="addTodo(todo._id)">Add</button>
</div>
#3
1
You can do it like this:
你可以这样做:
<input type="text" ng-model="todo.tag">