<FooterTemplate>
<asp:TextBox ID="txtSName" runat="server" Text=""/>
</FooterTemplate>
and the codebehind Code is as:
代码隐藏代码如下:
TextBox txtName = (TextBox)(GridView1.FooterRow.FindControl("txtSName"));
string aa=txtName.Text;
Everytime aa
is null
.
每次aa为空。
this code i m putting into the following:
我将这段代码放入以下内容中:
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
}
Please help me..........
请帮帮我..........
2 个解决方案
#1
1
Try This code it might work:
试试这段代码它可能有效:
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
TextBox txtName = GridView1.FooterRow.FindControl("txtSName") as TextBox;
string aa = txtName.Text;
}
#2
0
Try this :
尝试这个 :
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
TextBox txtName = (TextBox)e.Item.FindControl("txtSName");
}
Let me know if it is working. Are you using this to add/update
the record?
如果有效,请告诉我。您是否使用此添加/更新记录?
#1
1
Try This code it might work:
试试这段代码它可能有效:
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
TextBox txtName = GridView1.FooterRow.FindControl("txtSName") as TextBox;
string aa = txtName.Text;
}
#2
0
Try this :
尝试这个 :
protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
{
TextBox txtName = (TextBox)e.Item.FindControl("txtSName");
}
Let me know if it is working. Are you using this to add/update
the record?
如果有效,请告诉我。您是否使用此添加/更新记录?