I'm using Laravel. Here is a class I'm working on:
我正在使用Laravel。这是我正在研究的课程:
<?php
class InstagramController extends BaseController {
/*
|--------------------------------------------------------------------------
| Default Home Controller
|--------------------------------------------------------------------------
|
| You may wish to use controllers instead of, or in addition to, Closure
| based routes. That's great! Here is an example controller method to
| get you started. To route to this controller, just add the route:
|
| Route::get('/', 'HomeController@showWelcome');
|
*/
public function read($q)
{
$client_id = 'ea7bee895ef34ed08eacad639f515897';
$uri = 'https://api.instagram.com/v1/tags/'.$q.'/media/recent?client_id='.$client_id;
return sendRequest($uri);
}
public function sendRequest($uri){
$curl = curl_init($uri);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, 0);
curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, 0);
$response = curl_exec($curl);
curl_close($curl);
return $response;
}
}
The line:
这条线:
return sendRequest($uri);
Renders the error: Call to undefined function sendRequest()
呈现错误:调用未定义的函数sendRequest()
I'm assuming it's because I'm referencing the function in the wrong manner, but I can't find any explanations for how to do it.
我假设它是因为我以错误的方式引用该函数,但我找不到任何解释如何做到这一点。
2 个解决方案
#1
86
Try:
尝试:
return $this->sendRequest($uri);
Since PHP is not a pure Object-Orieneted language, it interprets sendRequest()
as an attempt to invoke a globally defined function (just like nl2br()
for example), but since your function is part of a class ('InstagramController'), you need to use $this
to point the interpreter in the right direction.
由于PHP不是纯粹的Object-Orieneted语言,它将sendRequest()解释为尝试调用全局定义的函数(例如,就像nl2br()),但由于你的函数是类的一部分('InstagramController'),你需要使用$ this将解释器指向正确的方向。
#2
3
Yes. Problem is in wrong notation. Use:
是。问题是错误的表示法。使用:
$this->sendRequest($uri)
Instead. Or
代替。要么
self::staticMethod()
for static methods. Also read this for getting idea of OOP - http://www.php.net/manual/en/language.oop5.basic.php
对于静态方法。另请阅读本文以了解OOP - http://www.php.net/manual/en/language.oop5.basic.php
#1
86
Try:
尝试:
return $this->sendRequest($uri);
Since PHP is not a pure Object-Orieneted language, it interprets sendRequest()
as an attempt to invoke a globally defined function (just like nl2br()
for example), but since your function is part of a class ('InstagramController'), you need to use $this
to point the interpreter in the right direction.
由于PHP不是纯粹的Object-Orieneted语言,它将sendRequest()解释为尝试调用全局定义的函数(例如,就像nl2br()),但由于你的函数是类的一部分('InstagramController'),你需要使用$ this将解释器指向正确的方向。
#2
3
Yes. Problem is in wrong notation. Use:
是。问题是错误的表示法。使用:
$this->sendRequest($uri)
Instead. Or
代替。要么
self::staticMethod()
for static methods. Also read this for getting idea of OOP - http://www.php.net/manual/en/language.oop5.basic.php
对于静态方法。另请阅读本文以了解OOP - http://www.php.net/manual/en/language.oop5.basic.php