I have to send two XML documents in my request to the UPS API (here's my original question What is the root of this XML document? )
我必须在请求中向UPS API发送两个XML文档(这是我原来的问题这个XML文档的根源是什么?)
How would I do this?
我该怎么办?
def make_initial_request
uri = URI.parse(UPS_API['confirm_url'])
https = Net::HTTP.new(uri.host, uri.port)
https.use_ssl = true
headers = {'Content-Type' => 'text/xml'}
request = Net::HTTP::Post.new(uri.path, headers)
request.body = xml_for_initial_request #<-- how do i split this into two documents?
#request.body = second_xml_document #<-- i want something like that. could i just use << ?
begin
response = https.request(request)
rescue
return nil
end
puts "response: #{response.code} #{response.message}: #{response.body}"
return nil if response.body.include?("Error")
end
1 个解决方案
#1
0
You should use MIME Multipart messages if the API support them (ruby gem). Otherwise just try to concatenate files' contents request.body = "#{xml_for_initial_request}\n#{second_xml_document}"
如果API支持它们,则应使用MIME Multipart消息(ruby gem)。否则只是尝试连接文件的内容request.body =“#{xml_for_initial_request} \ n#{second_xml_document}”
#1
0
You should use MIME Multipart messages if the API support them (ruby gem). Otherwise just try to concatenate files' contents request.body = "#{xml_for_initial_request}\n#{second_xml_document}"
如果API支持它们,则应使用MIME Multipart消息(ruby gem)。否则只是尝试连接文件的内容request.body =“#{xml_for_initial_request} \ n#{second_xml_document}”