字符串的JQuery过滤器数量[重复]

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Parsing an Int from a string in javascript 3 answers
在javascript 3答案中解析字符串中的Int

How do you filter only the numbers of a string?

你如何只过滤字符串的数字？

Example Pseudo Code:
number = $("thumb32").filternumbers()
number = 32

2 个解决方案

#1

You don't need jQuery for this - just plain old JavaScript regex replacement

你不需要jQuery - 只需简单的旧JavaScript正则表达式替换

var number = yourstring.replace(/[^0-9]/g, '')

var number = yourstring.replace（/ [^ 0-9] / g，''）

This will get rid of anything that's not [0-9]

这将摆脱任何不是[0-9]

Edit: Here's a small function to extract all the numbers (as actual numbers) from an input string. It's not an exhaustive expression but will be a good start for anyone needing.

编辑：这是一个小函数，用于从输入字符串中提取所有数字（作为实际数字）。这不是一个详尽的表达，但对任何需要的人来说都是一个良好的开端。

function getNumbers(inputString){
    var regex=/\d+\.\d+|\.\d+|\d+/g, 
        results = [],
        n;

    while(n = regex.exec(inputString)) {
        results.push(parseFloat(n[0]));
    }

    return results;
}

var data = "123.45,34 and 57. Maybe add a 45.824 with 0.32 and .56"
console.log(getNumbers(data));
// [123.45, 34, 57, 45.824, 0.32, 0.56];

#2

Not really jQuery at all:

根本不是jQuery：

number = number.replace(/\D/g, '');

That regular expression, /\D/g, matches any non-digit. Thus the call to .replace() replaces all non-digits (all of them, thanks to "g") with the empty string.

正则表达式/ \ D / g匹配任何非数字。因此，对.replace（）的调用用空字符串替换所有非数字（所有这些都由于“g”）。

edit — if you want an actual *number value, you can use parseInt() after removing the non-digits from the string:

编辑 - 如果你想要一个实际的*数字值，你可以在从字符串中删除非数字后使用parseInt（）：

var number = "number32"; // a string
number = number.replace(/\D/g, ''); // a string of only digits, or the empty string
number = parseInt(number, 10); // now it's a numeric value

If the original string may have no digits at all, you'll get the numeric non-value NaN from parseInt in that case, which may be as good as anything.

如果原始字符串可能根本没有数字，那么在这种情况下你将从parseInt获得数值非值NaN，这可能与任何东西一样好。

#1