I know that this:
我知道这个:
$("#id").html().split("<br>")[1];
gets 'Song name' from the HTML below.
从下面的HTML中获取“歌曲名称”。
How do I then wrap 'Song name' in a < span > in the HTML?
如何在HTML中的中包装“歌曲名称”?
HTML:
<a href="http://www.google.com" id="id">
252.
<br>
Song name
<br>
— Song Title
</a>
SOLVED!
See my answer below
请参阅下面的答案
3 个解决方案
#1
I guess wrapInner
function is what you are looking for
我想wrapInnerfunction就是你要找的东西
#2
I can see the logic in the other answers but neither of them worked. Seems as though I couldn't put anything after
我可以在其他答案中看到逻辑,但它们都没有奏效。好像我不能放任何东西
$("#id").html().split("<br>")[1]
...without it being deemed 'not a function' in console.
......没有它在控制台中被视为“不是一个功能”。
In the end I achieved what I wanted to by storing various chunks of code in variables and splicing them together e.g.
最后,我通过在变量中存储各种代码块并将它们拼接在一起,实现了我想要的目标,例如:
var middleLineOfTitle = data.response.posts[i].title.split("<br />")[1];
var middleLineOfTitleWrapped = "<span class='middleLineOfPostNameClass'>" + middleLineOfTitle + "</span>";
var entireTitle = data.response.posts[i].title.replace(middleLineOfTitle, middleLineOfTitleWrapped);
$('#recent-posts').append('<li><a href="' + data.response.posts[i].post_url +'"> ' + entireTitle + '</li>');
#3
Try this:
$("#id").html().split("<br>")[1].prepend("<span>").append("</span>");
#1
I guess wrapInner
function is what you are looking for
我想wrapInnerfunction就是你要找的东西
#2
I can see the logic in the other answers but neither of them worked. Seems as though I couldn't put anything after
我可以在其他答案中看到逻辑,但它们都没有奏效。好像我不能放任何东西
$("#id").html().split("<br>")[1]
...without it being deemed 'not a function' in console.
......没有它在控制台中被视为“不是一个功能”。
In the end I achieved what I wanted to by storing various chunks of code in variables and splicing them together e.g.
最后,我通过在变量中存储各种代码块并将它们拼接在一起,实现了我想要的目标,例如:
var middleLineOfTitle = data.response.posts[i].title.split("<br />")[1];
var middleLineOfTitleWrapped = "<span class='middleLineOfPostNameClass'>" + middleLineOfTitle + "</span>";
var entireTitle = data.response.posts[i].title.replace(middleLineOfTitle, middleLineOfTitleWrapped);
$('#recent-posts').append('<li><a href="' + data.response.posts[i].post_url +'"> ' + entireTitle + '</li>');
#3
Try this:
$("#id").html().split("<br>")[1].prepend("<span>").append("</span>");