Currently my program is in a spot where it both listens for the user to scroll a certain element, but also, at times, automatically scrolls this element by itself. (Not a gradual, pretty scroll, but an instant jump. It makes sense in context, I swear.)
目前我的程序位于一个位置,它既可以监听用户滚动某个元素,也可以自动滚动这个元素。 (不是一个渐进的,漂亮的卷轴,而是瞬间跳跃。我发誓在上下文中有道理。)
Is there a way to make the scroll event not trigger if the scrolling was done by setting scrollLeft or scrollTop? My first thought was a basic switch, like:
如果通过设置scrollLeft或scrollTop完成滚动,有没有办法使滚动事件不触发?我的第一个想法是一个基本的开关,如:
ignoreScrollEvents = true;
element.scrollLeft = x;
ignoreScrollEvents = false;
function onScroll() {
if(ignoreScrollEvents) return false;
}
but since events don't trigger immediately (oops, duhh), that's not a workable solution. What other sort of answers could I try? I'm also using jQuery, if that helps anything.
但由于事件不会立即触发(oops,duhh),这不是一个可行的解决方案。我可以尝试其他什么样的答案?我也在使用jQuery,如果这有帮助的话。
5 个解决方案
#1
19
Easiest generic method? Just reset the flag in the event handler. You'll want to check first if you're actually changing the value, as otherwise an event won't be fired - as Rodrigo notes, a good practice here is to factor this out into so-called "setter" functions:
最简单的通用方法?只需重置事件处理程序中的标志即可。如果您实际上正在更改值,您将首先检查,否则事件将不会被触发 - 正如Rodrigo所说,这里的一个好习惯是将其分解为所谓的“setter”函数:
function setScrollLeft(x)
{
if ( element.scrollLeft != x )
{
ignoreScrollEvents = true;
element.scrollLeft = x;
}
}
...
function onScroll()
{
var ignore = ignoreScrollEvents;
ignoreScrollEvents = false;
if (ignore) return false;
...
}
But, depending on your needs, you may already be storing the scroll position somewhere; if so, just update and check that as your flag. Something like:
但是,根据您的需要,您可能已经将滚动位置存储在某处;如果是这样,只需更新并检查它作为您的标志。就像是:
element.scrollLeft = currentScrollLeft = x;
...
function onScroll()
{
// retrieve element, etc...
if (element.scrollLeft == currentScrollLeft) return false;
...
}
#2
2
How about a setter?
安装者怎么样?
var _preventEvent = false; // set global flag
function setScrollTop(amount) {
_preventEvent = true; // set flag
document.documentElement.scrollTop = amount * Math.random();
}
function setScrollLeft(amount) {
_preventEvent = true; // set flag
document.documentElement.scrollLeft = amount * Math.random();
}
// scroll event listener
window.onscroll = function() {
console.clear();
if (_preventEvent) {
_preventEvent = false; // reset flag
return;
}
console.log('normal scroll');
}
html{ height:500%; width:500%; }
button{ position:fixed; }
button + button{ top:50px; }
<button onclick=setScrollTop(1000)>Random scrollTop</button>
<button onclick=setScrollLeft(1000)>Random scrollLeft</button>
#4
0
You could try storing the offset top of your element and matching it against the scrollTop when you step inside onScroll:
您可以尝试存储元素的偏移顶部,并在执行onScroll时将其与scrollTop匹配:
function onScroll(){
var scrollTop = (document.documentElement.scrollTop || document.body.scrollTop),
offsetTop = $('selector').offset().top;
if(offsetTop > scrollTop){
//user has not scrolled to element so do auto scrolling
}
}
#5
0
All right, my final solution, building off of Shog9 (not my real code, but my approach):
好吧,我的最终解决方案,建立Shog9(不是我真正的代码,但我的方法):
var oldScrollLeft = element.scrollLeft;
element.scrollLeft = x;
if(element.scrollLeft != oldScrollLeft) {
ignoreScrollEvents = true;
}
function onScroll() {
if(!ignoreScrollEvents) performGreatActions();
ignoreScrollEvents = false;
}
The if statement only sets the ignore flag when the scrollLeft value actually ends up changing, so cases like setting from 0 to 0 don't set the flag incorrectly.
if语句仅在scrollLeft值实际结束更改时设置ignore标志,因此设置从0到0的情况不会错误地设置标志。
Thanks, all!
谢谢,全部!
#1
19
Easiest generic method? Just reset the flag in the event handler. You'll want to check first if you're actually changing the value, as otherwise an event won't be fired - as Rodrigo notes, a good practice here is to factor this out into so-called "setter" functions:
最简单的通用方法?只需重置事件处理程序中的标志即可。如果您实际上正在更改值,您将首先检查,否则事件将不会被触发 - 正如Rodrigo所说,这里的一个好习惯是将其分解为所谓的“setter”函数:
function setScrollLeft(x)
{
if ( element.scrollLeft != x )
{
ignoreScrollEvents = true;
element.scrollLeft = x;
}
}
...
function onScroll()
{
var ignore = ignoreScrollEvents;
ignoreScrollEvents = false;
if (ignore) return false;
...
}
But, depending on your needs, you may already be storing the scroll position somewhere; if so, just update and check that as your flag. Something like:
但是,根据您的需要,您可能已经将滚动位置存储在某处;如果是这样,只需更新并检查它作为您的标志。就像是:
element.scrollLeft = currentScrollLeft = x;
...
function onScroll()
{
// retrieve element, etc...
if (element.scrollLeft == currentScrollLeft) return false;
...
}
#2
2
How about a setter?
安装者怎么样?
var _preventEvent = false; // set global flag
function setScrollTop(amount) {
_preventEvent = true; // set flag
document.documentElement.scrollTop = amount * Math.random();
}
function setScrollLeft(amount) {
_preventEvent = true; // set flag
document.documentElement.scrollLeft = amount * Math.random();
}
// scroll event listener
window.onscroll = function() {
console.clear();
if (_preventEvent) {
_preventEvent = false; // reset flag
return;
}
console.log('normal scroll');
}
html{ height:500%; width:500%; }
button{ position:fixed; }
button + button{ top:50px; }
<button onclick=setScrollTop(1000)>Random scrollTop</button>
<button onclick=setScrollLeft(1000)>Random scrollLeft</button>
#3
#4
0
You could try storing the offset top of your element and matching it against the scrollTop when you step inside onScroll:
您可以尝试存储元素的偏移顶部,并在执行onScroll时将其与scrollTop匹配:
function onScroll(){
var scrollTop = (document.documentElement.scrollTop || document.body.scrollTop),
offsetTop = $('selector').offset().top;
if(offsetTop > scrollTop){
//user has not scrolled to element so do auto scrolling
}
}
#5
0
All right, my final solution, building off of Shog9 (not my real code, but my approach):
好吧,我的最终解决方案,建立Shog9(不是我真正的代码,但我的方法):
var oldScrollLeft = element.scrollLeft;
element.scrollLeft = x;
if(element.scrollLeft != oldScrollLeft) {
ignoreScrollEvents = true;
}
function onScroll() {
if(!ignoreScrollEvents) performGreatActions();
ignoreScrollEvents = false;
}
The if statement only sets the ignore flag when the scrollLeft value actually ends up changing, so cases like setting from 0 to 0 don't set the flag incorrectly.
if语句仅在scrollLeft值实际结束更改时设置ignore标志,因此设置从0到0的情况不会错误地设置标志。
Thanks, all!
谢谢,全部!