如何使用XSL针对属性所在的特定节点运行模板？

For example, I'm trying to pick out the value "Application Library" from the following XML - ie, the value under content-node/localedata/title, where localedata@locale = "en".

例如,我试图从以下XML中选择值“Application Library” - 即content-node / localedata / title下的值,其中localedata @ locale =“en”。

<content-node objectid="6_NO2UF4I1186E1026H4BLVI08F1">
       <localedata locale="de">
            <title>Anwendungsbibliothek</title>
        </localedata>
        <localedata locale="en">
            <title>Application Library</title>
        </localedata>
        <localedata locale="es">
            <title>Biblioteca de aplicaciones</title>
        </localedata>
</content-node>

Specifically, what XPath expression do I put in the xsl:template@match value? I think it should be something like this, except I don't know how to match for the hardcoded value "en":

具体来说,我在xsl:template @ match值中添加了什么XPath表达式?我认为它应该是这样的,除了我不知道如何匹配硬编码值“en”:

<xsl:template match="localedata[@locale = en]">

Am I on the right track here, or is there some other way I should go about this?

我在这里是正确的轨道,还是有其他方式我应该这样做?

1 个解决方案

#1

I would say yes, you should be on the right track. I can't seem to find any samples to verify and confirm this - but you should have no trouble trying and verifying this.

我会说是的,你应该走在正确的轨道上。我似乎无法找到任何样本来验证和确认 - 但你应该没有尝试和验证这一点。

I say : go for it!

我说:去吧!

Looks like you'll have to adapt your XSL just a tiny bit:

看起来你必须调整你的XSL一点点:

<xsl:template match="localedata[@locale='en']">

With this (remove spaces after @locale, put the value in ' ... ') everything should be fine.

有了这个(删除@locale之后的空格,把值放在'...'),一切都应该没问题。

Marc

#1