I tried this code:
我试过这段代码:
<select name="selectedOption">
<option value="select"> Select </option>
<option value="option1"> option 1 </option>
<option value="option2"> option 2 </option>
</select>
<?php $selectedOption = $_POST['selectedOption']; ?>
<?php if($selectedOption == "option1") : ?>
<a href="#">This will only display if option 1 selected</a>
<?php elseif($selectedOption == "option2") : ?>
<a href="#">This will only display if option 2 selected</a>
<?php endif; ?>
But I get errors when I'm testing it on the web. The error that apears is "Notice: Undefined index: selectedOption in C:\wamp\www\vilaLuz\index.php on line 40"
但是当我在网上测试时,我会收到错误。 apears的错误是“注意:未定义的索引:第40行的C:\ wamp \ www \ vilaLuz \ index.php中的selectedOption”
What I am trying to do is get the option from the select and put a text under if option 1 is selected and a different text under if option 2 is selected, is that possible?
我想要做的是从选择中获取选项,如果选择了选项1,则在下面放置一个文本,如果选择了选项2,则选择不同的文本,这可能吗?
4 个解决方案
#1
1
<form action="" method="POST">
<select name="selectedOption">
<option value="select"> Select </option>
<option value="option1"> option 1 </option>
<option value="option2"> option 2 </option>
</select>
<input type="submit" value="post"/>
</form>
<?php if(isset($_POST['selectedOption'])) : ?>
<?php $selectedOption = $_POST['selectedOption']; ?>
<?php if($selectedOption == "option1") : ?>
<a href="#">This will only display if option 1 selected</a>
<?php elseif($selectedOption == "option2") : ?>
<a href="#">This will only display if option 2 selected</a>
<?php endif; ?>
<?php endif; ?>
#2
0
If you have not send your form, $_POST['selectedOption'] will be not set and empty!
如果您还没有发送表单,$ _POST ['selectedOption']将不会被设置为空!
So;
<?php $selectedOption = (!empty($_POST['selectedOption']) ? $_POST['selectedOption'] : ''); ?>
#3
0
You need to first check whether $_POST['selectedOption']
exists using isset
:
您需要首先使用isset检查$ _POST ['selectedOption']是否存在:
<?php
$selectedOption = isset($_POST['selectedOption'])
? $_POST['selectedOption']
: false;
?>
This is a ternary if
statement which sets the value of $selectedOption
to either the value of $_POST['selectedOption']
if it is set, or false
if it isn't.
这是一个三元if语句,它将$ selectedOption的值设置为$ _POST ['selectedOption']的值(如果已设置),如果不是,则设置为false。
#4
0
You should check to see if $_POST['selectedOption'] is set and is not empty. Empty() does these tests for you.
您应该检查$ _POST ['selectedOption']是否已设置且不为空。 Empty()为你做这些测试。
<?php
if (!empty($_POST['selectedOption'])) {
$selectedOption = $_POST['selectedOption'];
if($selectedOption == "option1") {
echo('<a href="#">This will only display if option 1 selected</a>');
}
elseif($selectedOption == "option2"){
echo('<a href="#">This will only display if option 2 selected</a>');
}
}
?>
#1
1
<form action="" method="POST">
<select name="selectedOption">
<option value="select"> Select </option>
<option value="option1"> option 1 </option>
<option value="option2"> option 2 </option>
</select>
<input type="submit" value="post"/>
</form>
<?php if(isset($_POST['selectedOption'])) : ?>
<?php $selectedOption = $_POST['selectedOption']; ?>
<?php if($selectedOption == "option1") : ?>
<a href="#">This will only display if option 1 selected</a>
<?php elseif($selectedOption == "option2") : ?>
<a href="#">This will only display if option 2 selected</a>
<?php endif; ?>
<?php endif; ?>
#2
0
If you have not send your form, $_POST['selectedOption'] will be not set and empty!
如果您还没有发送表单,$ _POST ['selectedOption']将不会被设置为空!
So;
<?php $selectedOption = (!empty($_POST['selectedOption']) ? $_POST['selectedOption'] : ''); ?>
#3
0
You need to first check whether $_POST['selectedOption']
exists using isset
:
您需要首先使用isset检查$ _POST ['selectedOption']是否存在:
<?php
$selectedOption = isset($_POST['selectedOption'])
? $_POST['selectedOption']
: false;
?>
This is a ternary if
statement which sets the value of $selectedOption
to either the value of $_POST['selectedOption']
if it is set, or false
if it isn't.
这是一个三元if语句,它将$ selectedOption的值设置为$ _POST ['selectedOption']的值(如果已设置),如果不是,则设置为false。
#4
0
You should check to see if $_POST['selectedOption'] is set and is not empty. Empty() does these tests for you.
您应该检查$ _POST ['selectedOption']是否已设置且不为空。 Empty()为你做这些测试。
<?php
if (!empty($_POST['selectedOption'])) {
$selectedOption = $_POST['selectedOption'];
if($selectedOption == "option1") {
echo('<a href="#">This will only display if option 1 selected</a>');
}
elseif($selectedOption == "option2"){
echo('<a href="#">This will only display if option 2 selected</a>');
}
}
?>