如何从输入XML中获取标记值，其中标记名存储在变量中

My code was unable to return a value from the input XML. The variable name is mapped in a separate xml based on a string.

我的代码无法从输入XML返回值。变量名在一个基于字符串的单独的xml中映射。

Step 1: I need to extract the XML tag from the another mapping XML. (This I got it)

步骤1:我需要从另一个映射XML中提取XML标记。(这我明白了)

Step 2: XML tag is saved in a variable and using the root tag, I am not able to get the value

步骤2:XML标记被保存在一个变量中，使用根标记，我无法获得该值

This is the XSLT:

这是XSLT:

    <xsl:template match="SUBSCRIBER">

            <xsl:variable name="expiry_date" select="$docStringAccountMapping/STRING_ACCOUNTS_LIST/STRING_ACCOUNTS_INFO[NSN_STRING='ThirdAccount']/AEXPIRY_DATE"/>

    <!-- this returns a string "EXPIRY_DATE_1" -->

            <xsl:value-of select="SUBSCRIBER/$expiry_date"/>


        </xsl:template>

This is the XML:

这是XML:

    <SUBSCRIBER>
        <EXPIRY_DATE_1>2014-07-09 23:59:59</EXPIRY_DATE_1>
    </SUBSCRIBER>

1 个解决方案

#1

First, you probably do not want to select "SUBSCRIBER...anything" if your template is matching SUBSCRIBER. The current node will be a SUBSCRIBER element, so start your XPath from there. Then...

首先，您可能不想选择“订阅者……”任何“如果您的模板匹配订阅者”。当前节点将是一个订阅者元素，因此从这里开始XPath。然后……

If $expiry_date includes the full element name including the namespace component:

如果$expiry_date包含包括名称空间组件的完整元素名称:

<xsl:value-of select="*[name()= $expiry_date]"/>

If $expiry_date includes only the element's local name excluding the namespace component:

如果$expiry_date只包含元素的本地名称，但是不包括命名空间组件:

<xsl:value-of select="*[local-name()= $expiry_date]"/>

#1