i'm using ImageShack API and this is my code:
我正在使用ImageShack API,这是我的代码:
<form method="post" enctype="multipart/form-data" action="http://www.imageshack.us/upload_api.php?">
<p><input type="file" name="fileupload"></p>
<p>Tags:<input type="text" name="tags" value=""></p>
<p><input type="text" name="key" value="xxxx"></p>
<p><select name="optsize">
<option value="320x240">Small (320x240)</option>
<option value="426x320" selected>Medium (426x320)</option>
<option value="640x480">Big (640x480)</option>
</select></p>
<p><input type="submit" value="Go"></p>
</form>
It works fine, but when i click 'Go' appears in my web browser the whole file XML that came as response, i need get this response in my servlet or JSP.
它工作正常,但是当我点击“Go”在我的Web浏览器中出现作为响应的整个文件XML时,我需要在我的servlet或JSP中获得此响应。
How do i get this XML response ?
我如何获得此XML响应?
Best regards, Valter Henrique.
此致,Valter Henrique。
1 个解决方案
#1
0
You need to make the mutlipart post request from your servlet.
您需要从servlet发出mutlipart post请求。
HttpClient would enable you to do this. That's fairly involved but I think this is a good example of how to do it.
HttpClient可以让你这样做。这是相当复杂的,但我认为这是如何做到这一点的一个很好的例子。
http://evgenyg.wordpress.com/2010/05/01/uploading-files-multipart-post-apache/
#1
0
You need to make the mutlipart post request from your servlet.
您需要从servlet发出mutlipart post请求。
HttpClient would enable you to do this. That's fairly involved but I think this is a good example of how to do it.
HttpClient可以让你这样做。这是相当复杂的,但我认为这是如何做到这一点的一个很好的例子。
http://evgenyg.wordpress.com/2010/05/01/uploading-files-multipart-post-apache/