I have a xml file as below:
我有一个xml文件如下:
<?xml version="1.0" encoding="UTF-8"?>
<kml xmlns="http://www.opengis.net/kml/2.2">
<Document><name>My document</name>
<description>Content</description>
<Style id="Lump">
<LineStyle><color>CD0000FF</color><width>2</width></LineStyle>
<PolyStyle><color>9AFF0000</color></PolyStyle>
</Style>
<Style id="Path">
<LineStyle><color>FF0000FF</color><width>3</width></LineStyle>
</Style>
<Style id="markerstyle">
<IconStyle><Icon><href>
http://maps.google.com/intl/en_us/mapfiles/ms/micons/red-dot.png
</href></Icon></IconStyle>
</Style>
<Placemark><name>NAME</name>
<description>YES</description>
<styleUrl>#Path</styleUrl>
<LineString>
<tessellate>1</tessellate>
<altitudeMode>clampToGround</altitudeMode>
<coordinates>
12.656250,41.454049,0.0
12.676849,41.454049,0.0
12.693329,41.448903,0.0
12.746887,41.418015,0.0
12.936401,41.370625,0.0
12.966614,41.351041,0.0
12.992706,41.323201,0.0
13.010559,41.298444,0.0
13.024292,41.293285,0.0
13.024292,41.287094,0.0
</coordinates>
</LineString>
</Placemark>
</Document>
</kml>
And I need to get the value "coordinates" and transform each value from decimal to hours/minutes.
我需要获取值“坐标”并将每个值从十进制转换为小时/分钟。
I already made the class to convert the value:
我已经让类转换了值:
public ConvertCooDecToLatLong(Double latDec, Double lonDec) {
latH = (double) latDec.intValue();
latM = (double)(new Double((latDec - latH) * 60.0).intValue());
latS = (new Double(((latDec - latH) * 60.0) - latM) * 60);
lonH = (double) latDec.intValue();
lonM = (double)(new Double((latDec - lonH) * 60.0).intValue());
lonS = (new Double(((latDec - lonH) * 60.0) - lonM) * 60);
if (latDec > 0) {
dirLat = "N";
} else {
dirLat = "S";
}
if (lonDec > 0) {
dirLong = "E";
} else {
dirLong = "W";
}
coord = new LLEle("TEST", latH, latM, latS, dirLat, lonH, lonM, lonS, dirLong);
}
But I don't know if is it possible to get the input from that xml file.
但我不知道是否有可能从该xml文件中获取输入。
I read some posts but, probably my fault, I still don't get it.
我读了一些帖子但是,可能是我的错,我仍然没有得到它。
Can anyone explain me how to do it?
任何人都可以解释我该怎么做?
If possible with some examples.
如果可能,举一些例子。
Thanks.
1 个解决方案
#1
1
Could you please try following solution:
您可以尝试以下解决方案:
import java.io.File;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.xml.sax.SAXException;
public class Test {
public static void main(String[] args) throws Exception {
Test test = new Test();
String str = test.getCoordinatesContent("D:/test.xml");
System.out.println(str);
}
public String getCoordinatesContent(String filePath)throws ParserConfigurationException, SAXException, IOException {
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(new File(filePath));
doc.getDocumentElement().normalize();
return doc.getElementsByTagName("coordinates").item(0).getTextContent().trim();
}
}
#1
1
Could you please try following solution:
您可以尝试以下解决方案:
import java.io.File;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.xml.sax.SAXException;
public class Test {
public static void main(String[] args) throws Exception {
Test test = new Test();
String str = test.getCoordinatesContent("D:/test.xml");
System.out.println(str);
}
public String getCoordinatesContent(String filePath)throws ParserConfigurationException, SAXException, IOException {
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(new File(filePath));
doc.getDocumentElement().normalize();
return doc.getElementsByTagName("coordinates").item(0).getTextContent().trim();
}
}