jQuery，使用.each获取类中每个元素的ID？

I'm trying this to get the id of each element in a class but instead it's alerting each name of the class separately, so for class="test" it's alerting: t, e, s, t... Any advice on how to get the each element id that is part of the class is appreciated, as I can't seem to figure this out.. Thanks.

我正在尝试这个来获取类中每个元素的id但是它分别警告类的每个名称，所以对于class =“test”它的警告：t，e，s，t ...有关如何的任何建议得到每个元素id是该类的一部分是值得赞赏的，因为我似乎无法弄清楚这一点..谢谢。

$.each('test', function() { 
   alert(this)
});

2 个解决方案

#1

122

Try this, replacing .myClassName with the actual name of the class (but keep the period at the beginning).

试试这个，将.myClassName替换为类的实际名称（但将句点保留在开头）。

$('.myClassName').each(function() {
    alert( this.id );
});

So if the class is "test", you'd do $('.test').each(func....

因此，如果课程是“测试”，你会做$（'。test'）。每个（函数....

This is the specific form of .each() that iterates over a jQuery object.

这是迭代jQuery对象的.each（）的特定形式。

The form you were using iterates over any type of collection. So you were essentially iterating over an array of characters t,e,s,t.

您使用的表单会迭代任何类型的集合。所以你基本上迭代了一个字符数组t，e，s，t。

Using that form of $.each(), you would need to do it like this:

使用$ .each（）的形式，你需要这样做：

$.each($('.myClassName'), function() {
    alert( this.id );
});

...which will have the same result as the example above.

...将与上面的示例具有相同的结果。

#2

patrick dw's answer is right on.

帕特里克dw的回答是正确的。

For kicks and giggles I thought I would post a simple way to return an array of all the IDs.

对于踢腿和咯咯笑声，我想我会发布一个简单的方法来返回所有ID的数组。

var arrayOfIds = $.map($(".myClassName"), function(n, i){
  return n.id;
});
alert(arrayOfIds);

#1

122